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3 years ago

Six times the sum of a number and eight is nineteen . Which of the following equations could be used to find the number

Mathematics

1 answer:

Butoxors [25]3 years ago

6 0

Answer:

6x = -29 (Bear in mind I can't see all of the options you can pick from, so this is the closest I can get.)

Step-by-step explanation:

First, write out the equation.

6(8 + x) = 19. x is our unknown, or our variable.

Now, simplify the equation.

6(8 + x) = 19

48+ 6x = 19

Next, isolate the variable (get the variable alone)

48 + 6x = 19

-48 -48

6x = -29.

Finally, solve (Your solution should lay along the lines of the equation directly above this, but if it wants the solution here it is.)

6x = -29

/6 /6

x = -4.8333

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Steve likes to entertain friends at parties with "wire tricks." Suppose he takes a piece of wire 60 inches long and cuts it into

Alex_Xolod [135]

Answer:

a) the length of the wire for the circle = $(\frac{60\pi }{\pi+4}) in$

b)the length of the wire for the square = $(\frac{240}{\pi+4}) in$

c) the smallest possible area = 126.02 in² into two decimal places

Step-by-step explanation:

If one piece of wire for the square is y; and another piece of wire for circle is (60-y).

Then; we can say; let the side of the square be b

so 4(b)=y

b= $\frac{y}{4}$

Area of the square which is L² can now be said to be;

$A_S=(\frac{y}{4})^2 = \frac{y^2}{16}$

On the otherhand; let the radius (r) of the circle be;

2πr = 60-y

$r = \frac{60-y}{2\pi }$

Area of the circle which is πr² can now be;

$A_C= \pi (\frac{60-y}{2\pi } )^2$

$=( \frac{60-y}{4\pi } )^2$

Total Area (A);

A = $A_S+A_C$

= $\frac{y^2}{16} +(\frac{60-y}{4\pi } )^2$

For the smallest possible area; $\frac{dA}{dy}=0$

∴ $\frac{2y}{16}+\frac{2(60-y)(-1)}{4\pi}=0$

If we divide through with (2) and each entity move to the opposite side; we have:

$\frac{y}{18}=\frac{(60-y)}{2\pi}$

By cross multiplying; we have:

2πy = 480 - 8y

collect like terms

(2π + 8) y = 480

which can be reduced to (π + 4)y = 240 by dividing through with 2

$y= \frac{240}{\pi+4}$

∴ since $y= \frac{240}{\pi+4}$ , we can determine for the length of the circle ;

60-y can now be;

= $60-\frac{240}{\pi+4}$

= $\frac{(\pi+4)*60-240}{\pi+40}$

= $\frac{60\pi+240-240}{\pi+4}$

= $(\frac{60\pi}{\pi+4})in$

also, the length of wire for the square (y) ; $y= (\frac{240}{\pi+4})in$

The smallest possible area (A) = $\frac{1}{16} (\frac{240}{\pi+4})^2+(\frac{60\pi}{\pi+y})^2(\frac{1}{4\pi})$

= 126.0223095 in²

≅ 126.02 in² ( to two decimal places)

4 0

4 years ago

What is 3.06 rounded each number to the nearest tenths?

g100num [7]

3.1
......................

6 0

3 years ago

I need help please!!!!!!!

shusha [124]

its an obtuse angle

4 0

3 years ago

Read 2 more answers

Please help with this question picture attached ASAP please

olga nikolaevna [1]

1 : 1.71 : 2.43

Step-by-step explanation:

What divided by 7= 1?

7/7 = 1

So use that answer for the other two dolls.

12/7 = 1.71

17/7 = 2.43

1 : 1.71 : 2.43

Have the same ratio as

7 : 12 : 17

5 0

3 years ago

What are the intercepts of 5x = 2y +4??

iVinArrow [24]

The y intercepts are when x=0 (the line crosses the y axis) and the x intercepts are when y=0 (the line crosses the x axis). Plugging x=0 in, we get 5*0=2y+4. Subtracting 4 from both sides, we get -4=2y and by dividing both sides by 2 we get y=-2, for one intercept to be (0, -2). For the other intercept, we make y=0 to get 5x=2*0+4=4. Dividing both sides by 4, we get x=4/5, making our other intercept (4/5, 0)

5 0

3 years ago