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Hatshy [7]
2 years ago
10

In 1990, Dawn gross pay was $48,000.

Mathematics
1 answer:
forsale [732]2 years ago
4 0

A. Dawn's gross monthly pay is<em> $4,000</em> ($48,000/12).

B. The month that Dawn hit her maximum taxable Social Security Income is May (5 months from January to May).

C. In February, 1978, Dawn paid <em>$260</em> in Social Security Tax.

D. In May, 1978, Dawn paid <em>$110.50</em> in Social Security Tax, which represented the balance.

E. In November, 1978, Dawn paid <em>$0</em> in Social Security Tax because by May she had completely paid the maximum Social Security Tax of $1,150.50.

<h3>Data and Calculations:</h3>

Gross earnings in 1990 = $48,000

Maximum taxable income in 1990 = $17,700

Social Security Tax Rate = 6.5%

Gross monthly pay = $4,000 ($48,000/12)

Monthly Social Security Tax = $260 ($4,000 x 6.5%)

Total Social Security Tax = $1,150.50 ($17,700 x 6.5%)

In 5 months, Dawn would have paid a <em>total of $1,150.50</em> ($260 x 4 + $110.50) in Social Security Tax.

Thus, the total Social Security Tax paid by Dawn in that year was <em>$1,150.50.</em>

Learn more about Social Security Tax here: brainly.com/question/9741758

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Andrej [43]

This rule shows how we transition the x-coordinate and y-coordinate when finding B'.


In this rule, it shows us what to add/subtract from the x-value and y-value in the coordinate. We can see that it wants us to subtract 5 from the x-value (based on the "x - 5") and that it wants us to add 9 to the y-value (based on the "y + 9"). Based on this information, we can find B':

\textrm{B}'(6 - 5, -3 + 9)

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3 years ago
Gus started with a number he multiplied by 8 subtracted 12 divided by 4 and added 7 to get 50 show how to work backward to find
DanielleElmas [232]

Answer:

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Step-by-step explanation:

This equation can be derived from the question

let a represent the initial number Gus started with

{[(a x 8) - 12] / 4 } + 7 = 50

subtract 7 from both sides of the equation

[(a x 8) - 12] / 4 } = 43

Multiply both sides of the equation by 4

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Divide both sides by 8

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2 years ago
Evaluate the integral
Kruka [31]

Hello, please consider the following.

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\displaystyle (25-1)\int\limits^x {5sin(5t)sin(t)} \, dt= +5sin(5x)cos(x)-25cos(5x)sin(x)

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\displaystyle \Large \boxed{\sf \bf\int\limits^x {5sin(5t)sin(t)} \, dt=\dfrac{5sin(5x)cos(x)-25cos(5x)sin(x)}{24}+C}

Thanks

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What point is marked on the number line?
dolphi86 [110]
The answer would be -7/8. Hope this helps!
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