What is the slope of the diagonal line on the larger triangle? Explain how you found it.

Mathematics

1 answer:

Stolb23 [73]2 years ago

5 0

Answer: 2/3 is the slope I think and for the same slope thing here is my answer:

We can use similarly of triangles in this case there will be a formation of 2 pairs equal ( angles formed by the y-axis on the parallel lines) angles between triangles formed as the y-axis lines are parallel. So,the slope is the same for both.

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Questions 13 and 17 if anybody knows ?

jenyasd209 [6]

13) If T(n) = 2n-7, what is the 5th term?
n is the number of the term you are looking for. In this instance, n is equal to 5.

T(5) = 2(5) - 7
T(5) = 10 -7
T(5) = 3

The 5th term is 3.

17) inequality based on the line number.
Since the line does not extend in any direction outward. It means that the range should be within -3 and 3.
Solid circle means that -3 is equivalent to x
hollow ciccle means that 3 is not x.

-3 < x < 3

x = any number from -3 upto 2.

8 0

3 years ago

a system of equations is shown below: x y = 3 2x − y = 6 the x−coordinate of the solution to this system of equations is _____.

pychu [463]

If you would like to solve the system of equations x + y = 3 and 2x - y = 6, you can do this using the following steps:

x + y = 3 ... y = 3 - x
2x - y = 6
_________
2x - y = 6
2x - (3 - x) = 6
2x - 3 + x = 6
3x = 6 + 3
3x = 9 /3
x = 9/3
x = 3

y = 3 - x = 3 - 3 = 0

The correct result would be x = 3.

6 0

3 years ago

Two trains travel a 160 km track each day. The express travels 10 km h^-1 faster and take 30 minutes less time than the normal t

aniked [119]

Let s = the speed of the slower train in km/hrs+10 = the speed of the faster train in km/hrLet t = time in hrs for the slower train to go 160 kmt-5 = time in hrs for faster train to go 160 km---------------Slower train:(1)
160=s.t

Faster train:(2) 160=(s+10) .(t-.5)From (1)(1) t=160/s
use the relations given in following screenshot and then use quadratic equation.