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Alex
3 years ago
15

Makayla is reading a 400 page book for her book club. she reads 32 pages each hour

Mathematics
1 answer:
Vikki [24]3 years ago
5 0
What’s the question ? that’ll help us know !
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Solve for n. 4n + 19 + 13n = -13 + 15n
STALIN [3.7K]
ANSWER: n = -16

4n + 13n = 17n

19 + 13 = 32

15 - 17 = -2

n = -16
3 0
3 years ago
Read 2 more answers
How many feet are in 100 inches? Write your answer two ways: in feet and inches and in feet only
jolli1 [7]

Answer: 8 ft and 4 in, 8 1/3 ft

Step-by-step explanation:

100/12=50/6=25/3=8.3333333...

1/3 of a foot is 1/3x12 which is 12/3 which is 4 in.

3 0
3 years ago
Help please! write an expression that shows how to convert kilograms to grams
Irina18 [472]

Kilo is the unit prefix for multiplication by one thousand. Therefore, a kilogram, or kg, is equal to one thousand grams. To convert grams to kilograms, you simply have to multiply the number of kilograms to grams.

So, for example, if you had 16.24kg of a compound, it would equal:

3 0
3 years ago
Read 2 more answers
*In ∆ABC, on the extension of the side BC , draw a line segment CD ≅ CA . Draw the segment AD . The line segment CE is the angle
Leya [2.2K]

CE ⊥ CF because m∠ECA + m∠FCA = 90°

Step-by-step explanation:

In ∆ABC

  • On the extension of the side BC , draw a line segment CD ≅ CA
  • Draw the segment AD
  • The line segment CE is the angle bisector of ∠ACB
  • The line segment CF is the median towards AD in ∆ ACD

We want to prove that CF ⊥ CE

Look to the attached figure

In Δ ABC

∵ CE is the bisector of angle ACB

∴ ∠ACE ≅ ∠BCE

In Δ ACD

∵ CA = CD

∴ Δ ACD is an isosceles triangle

∵ AD is the median towards AD

- In any isosceles triangle the median from a vertex to its opposite

  side bisects this vertex

∴ AD bisects ∠ACD

∴ ∠ACF ≅ ∠DCF

∵ BCD is a straight segment

∵ CE , CA , CF are drawn from point C

∴ m∠BCE + m∠ACE + m∠ACF + m∠DCF = 180°

∵ m∠ACE ≅ m∠BCE

∵ m∠ACF ≅ m∠DCF

- Replace m∠BCE by m∠ACE and m∠DCF by m∠ACF

∴ m∠ACE + m∠ACE + m∠ACF + m∠ACF = 180°

∴ 2 m∠ACE + 2 m∠ACF = 180°

- Divide all terms by 2

∴ m∠ACE + m∠ACF = 90°

∴ EC ⊥ CF

CE ⊥ CF because m∠ECA + m∠FCA = 90°

Learn more:

You can learn more about perpendicular lines in brainly.com/question/11223427

#LearnwithBrainly

7 0
3 years ago
What is the mass of a copper (II) chloride sample if it contains 0.0344 moles of the compound?
ale4655 [162]

According to the valence number of copper(2+) and the same value for chlorine (1-) copper (II) chloride has the formula of CuCl2

The molar mass of copper is 0,0635 kg/mole and chlorine gas a molar mass of 0,035 kg/mole the compound will have a molar mass of ( 0,0635+2×0,035 )kg/mole=0,099kg/mole and 0,344 moles are equivalent in mass to 0,344×0,135 kg=0,046 kg

5 0
2 years ago
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