Question

obtain the equation of two points passing of lines 4x-3y-1=0 and 2x-3y+3=0 and equally inclined to the axes​

Answer 1

Answer:By 8(4)P.5, the slope of the line equally inclined to axes is tan(±45  

o

)=±1. Hence by P+λQ=0,

5λ+3

2λ+4

​

=±1

⇒λ=  

3

1

​

,−1. Putting for λ, the two lines are

x−y=0,x+y−2=0.

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