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Debora [2.8K]
3 years ago
8

Which number line represents the solutions to -2/x = -6?

Mathematics
2 answers:
Alex Ar [27]3 years ago
8 0

Step-by-step explanation:

\\ \sf\longmapsto -2|x|=-6

\\ \sf\longmapsto |x|=\dfrac{-6}{-2}

\\ \sf\longmapsto |x|=3

Hence

\\ \sf\longmapsto x\in (-3,3)

Option D is correct

anygoal [31]3 years ago
5 0

Answer:

{ \tt{ - 2 |x|  =  - 6}} \\  \\ { \tt{ |x|  = 3}} \\  \\{ \tt{  \{ - 3 \leqslant x \leqslant 3 \}}}

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Find the value of x.<br> a.17<br> b.12<br> c.40<br> d.18<br> e.none are correct
Natali5045456 [20]

Answer:

b.12

Step-by-step explanation:

<u>Key skills needed: Interior Angle Measure Theorem, Equation Creation</u>

1) First, we need to classify this shape. It has 7 sides, which means that we can use the Interior angle Theorem to find out the sum of all the interior angle measures

The theorem is:    S = (n - 2)180

S is the sum of all interior angle measures

n is the number of sides of the polygon

2) With this, we can plug in 7 for "n" (Since the figure has 7 sides) and get:

---> S = (7-2)180

---> (7-2) is 5 since 7 - 2 = 5 so --> S = 5(180)

---> 5(180) is the same as 5 x 180 which is 900 so --> S = 900

This means that the sum of all interior angles is 900 degrees.

3) Now, we have to find out the sum of all the angles that they gave us so:

---> 10x + 10x + 9 + 133 + 9x + 14 + 12x - 9 + 10x + 5 + 136 = 900

The left side is the sum of all interior angles in the shape, and the right side is what the sum should be when expressed as a number.

4) We have to combine all like terms on the left side:

---> 10x + 10x + 9x + 12x + 10x = 51x

---> 9 + 133 + 14 -9+5+136 = 288    

5) This means that ---> 51x + 288 = 900

Subtract 288 from both sides  and get:

---> 51x = 612    (900-288 = 612)

Then divide by 51 from both sides and get:

---> x = 12     (612 ÷ 51 = 12)

Therefore b.12 is your answer.

<em>Hope you understood and have a nice day!! :D</em>

8 0
3 years ago
What is congruent of a triangle
Korvikt [17]

Answer:

When two triangles have the exact 3 sides and the same 3 angles

Step-by-step explanation:

In geometry, triangles are congruent when the have the exact same 3 sides and the exact same 3 angles. They can be flipped or reflected, they just have to have same sides and angles

4 0
4 years ago
P=−4b 2 +6b−9 <br> Q=7b 2 −2b−5<br> ​P−Q=<br> Your answer should be a polynomial in standard form.
shepuryov [24]

Answer:

−11b^2+8b−4

Step-by-step explanation:

−4b2+6b−9−7b2+2b+5

Simplify by adding terms.

11b2+8b−4

3 0
3 years ago
Factor the trinomial<br><br> X2-12x +16
wlad13 [49]
2*&/45/+=67364/3/4/32:5,6544 is hothead answer
6 0
3 years ago
How to find the vertex calculus 2What is the vertex, focus and directrix of x^2 = 6y
son4ous [18]

Solution:

Given:

x^2=6y

Part A:

The vertex of an up-down facing parabola of the form;

\begin{gathered} y=ax^2+bx+c \\ is \\ x_v=-\frac{b}{2a} \end{gathered}

Rewriting the equation given;

\begin{gathered} 6y=x^2 \\ y=\frac{1}{6}x^2 \\  \\ \text{Hence,} \\ a=\frac{1}{6} \\ b=0 \\ c=0 \\  \\ \text{Hence,} \\ x_v=-\frac{b}{2a} \\ x_v=-\frac{0}{2(\frac{1}{6})} \\ x_v=0 \\  \\ _{} \\ \text{Substituting the value of x into y,} \\ y=\frac{1}{6}x^2 \\ y_v=\frac{1}{6}(0^2) \\ y_v=0 \\  \\ \text{Hence, the vertex is;} \\ (x_v,y_v)=(h,k)=(0,0) \end{gathered}

Therefore, the vertex is (0,0)

Part B:

A parabola is the locus of points such that the distance to a point (the focus) equals the distance to a line (directrix)

Using the standard equation of a parabola;

\begin{gathered} 4p(y-k)=(x-h)^2 \\  \\ \text{Where;} \\ (h,k)\text{ is the vertex} \\ |p|\text{ is the focal length} \end{gathered}

Rewriting the equation in standard form,

\begin{gathered} x^2=6y \\ 6y=x^2 \\ 4(\frac{3}{2})(y-k)=(x-h)^2 \\ \text{putting (h,k)=(0,0)} \\ 4(\frac{3}{2})(y-0)=(x-0)^2 \\ Comparing\text{to the standard form;} \\ p=\frac{3}{2} \end{gathered}

Since the parabola is symmetric around the y-axis, the focus is a distance p from the center (0,0)

Hence,

\begin{gathered} Focus\text{ is;} \\ (0,0+p) \\ =(0,0+\frac{3}{2}) \\ =(0,\frac{3}{2}) \end{gathered}

Therefore, the focus is;

(0,\frac{3}{2})

Part C:

A parabola is the locus of points such that the distance to a point (the focus) equals the distance to a line (directrix)

Using the standard equation of a parabola;

\begin{gathered} 4p(y-k)=(x-h)^2 \\  \\ \text{Where;} \\ (h,k)\text{ is the vertex} \\ |p|\text{ is the focal length} \end{gathered}

Rewriting the equation in standard form,

\begin{gathered} x^2=6y \\ 6y=x^2 \\ 4(\frac{3}{2})(y-k)=(x-h)^2 \\ \text{putting (h,k)=(0,0)} \\ 4(\frac{3}{2})(y-0)=(x-0)^2 \\ Comparing\text{to the standard form;} \\ p=\frac{3}{2} \end{gathered}

Since the parabola is symmetric around the y-axis, the directrix is a line parallel to the x-axis at a distance p from the center (0,0).

Hence,

\begin{gathered} Directrix\text{ is;} \\ y=0-p \\ y=0-\frac{3}{2} \\ y=-\frac{3}{2} \end{gathered}

Therefore, the directrix is;

y=-\frac{3}{2}

3 0
1 year ago
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