So, use the distance between two points formula:squareroot((x2-x1)^2+(y2-y1)^2)
squareroot((-7--4)^2+(8-7)^2)
squareroot((-3)^2+(1)^2)
squareroot((9+1)
squareroot(10)
squareroot 10 can be simplified to 3.2 units
You can factor out a 5n to get
5n(4m-3)
Answer:
The volume of the water is 56520 cubic cm
Step-by-step explanation:
Radius of hemispherical bowl = 30 cm
Depth of water in bowl = 12 cm
Volume of hemispherical bowl = ![\frac{2}{3} \pi r^3](https://tex.z-dn.net/?f=%5Cfrac%7B2%7D%7B3%7D%20%5Cpi%20r%5E3)
Volume of hemispherical bowl = ![\frac{2}{3} \times 3.14 \times 30^3](https://tex.z-dn.net/?f=%5Cfrac%7B2%7D%7B3%7D%20%5Ctimes%203.14%20%5Ctimes%2030%5E3)
Volume of hemispherical bowl = ![56520 cm^3](https://tex.z-dn.net/?f=56520%20cm%5E3)
So, there is 56520 cubic cm water in hemispherical bowl
Hence the volume of the water is 56520 cubic cm