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3 years ago

Write a word problem whose solutions is |20| =20

1 answer:

5 0

You have 20 candies together in abag 10 red 10 green tou mix them yp togethr in a bag how many candies do you have in the bag

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HELP NOW You will not use all of the pieces.

Elanso [62]

Answer:

Step-by-step explanation:

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2 years ago

How to solve polynomials

svp [43]

Using PADMAS really works

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3 years ago

3. Crystal has decided to drive her new car on the west coast from California to Washington, which is about 930

antoniya [11.8K]

Answer:

The correct option is the first graph (Yes)

Step-by-step explanation:

The given function is W(d) = 930/d

Where;

W(d) = The number of days it would take to get to Washington

d = The distance travelled each day in miles

We note that the given graphs have number of days in the y-axis and the miles in the x-axis, and that in the function, the distance Crystal travels each day is constant, d, while the 930 is the total distance from California to Washington, while W(d) is the time

Therefore, the variables for crystal are W(d) and the part of 930 miles completed, while the constant is the speed, d = miles/day, which gives;

W(d) = 930/d

W(d) ∝ Part of 930 miles completed × Constant

∴ W(d) which is the time is directly proportional to the distance

The graph which represents the number of days, W(d) it will take Crystal to get to Washington (miles completed) as a function of distance traveled per day, d, which is constant is a straight line graph which is the first graph

7 0

2 years ago

Help with 5b please . thank you.

Allushta [10]

Answer:

See explanation

Step-by-step explanation:

We are given f(x)=ln(1+x)-x+(1/2)x^2.

We are first ask to differentiate this.

We will need chain rule for first term and power rule for all three terms.

f'(x)=(1+x)'/(1+x)-(1)+(1/2)×2x

f'(x)=(0+1)/(1+x)-(1)+x

f'(x)=1/(1+x)-(1)+x

We are then ask to prove if x is positive then f is positive.

I'm thinking they want us to use the derivative part in our answer.

Let's look at the critical numbers.

f' is undefined at x=-1 and it also makes f undefined.

Let's see if we can find when expression is 0.

1/(1+x)-(1)+x=0

Find common denominator:

1/(1+x)-(1+x)/(1+x)+x(1+x)/(1+x)=0

(1-1-x+x+x^2)/(1+x)=0

A fraction can only be zero when it's numerator is.

Simplify numerator equal 0:

x^2=0

This happens at x=0.

This means the expression,f, is increasing or decreasing after x=0. Let's found out what's happening there. f'(1)=1/(1+1)-(1)+1=1/2 which means after x=0, f is increasing since f'>0 after x=0.

So we should see increasing values of f when we up the value for x after 0.

Plugging in 0 gives: f(0)=ln(1+0)-0+(1/2)0^2=0.

So any value f, after this x=0, should be higher than 0 since f(0)=0 and f' told us f in increasing after x equals 0.

8 0

2 years ago

6m+17-13+5n combine like terms

lana [24]

Answer:

hmmmm bilmim weantremlo ?

3 0

2 years ago

Read 2 more answers