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3 years ago

An electron has _____.

2 answers:

max2010maxim [7]3 years ago

8 0

An electron has a negatively charged sub atomic particles.

And you could also say that an electron has a negatively charged sub atomic particles in a cloud around the nucleus of an atom. Do what you would prefer.
:) :)

vichka [17]3 years ago

5 0

Electrons have a mass of 1/1836
Hope that helps you!

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g An analytical chemist is titrating of a solution of diethylamine with a solution of . The of diethylamine is . Calculate the p

Serga [27]

Answer:

90% of people marry there 7th grade love. since u have read this, u will be told good news tonight. if u don't pass this on nine comments your worst week starts now this isn't fake. apparently if u copy and paste this on ten comments in the next ten minutes you will have the best day of your life tomorrow. you will either get kissed or asked out in the next 53 minutes someone will say i love you

Explanation:

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3 years ago

Do you know the answer to this question?

Yakvenalex [24]

Yes i do know what this question is.

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4 years ago

Which three elements are liquid at 25 degrees Celsius

KengaRu [80]

Answer:

Bromine and mercury are liquid at room temperature and gallium is liquid when just a little above room temperature. Originally Answered: What are the only two elements that are liquid at 25° C (room temperature)? Mercury and Bromine. Mercury is solid below -38 degrees F (-39C) and Bromine below 19 degrees F (-7.2C).

Explanation:

5 0

3 years ago

Read 2 more answers

Which statements are true? The oxidation number for Cu(s) is +2. An oxidizing agent gains electrons. Na+ is formed from the redu

just olya [345]

Answer: The correct statements are:

An oxidizing agent gains electrons and $Zn^{2+}$ is formed from the oxidation of Zn(s).

Explanation:

For the given options:

Statement 1: The oxidation number for Cu(s) is +2

Copper is the 29th element of the periodic table having electronic configuration of $[Ar]3d^{10}4s^1$

This element can show +1 or +2 oxidation states. Thus, this statement is false.

Statement 2: An oxidizing agent gains electrons.

Oxidizing agents are defined as the agents which oxidize other substance and itself gets reduced. These agents undergoes reduction reactions and reduction reaction is the reaction in which an atom gains electrons.

Thus, this statement is True.

Statement 3: $Na^+$ is formed from the reduction of Na(s)

Oxidation reaction is defined as the reaction in which an atom looses its electrons. Here, oxidation state of the atom increases.

$X\rightarrow X^{n+}+ne^-$

Sodium is the 11th element and it will loose electrons to form sodium ion.

$Na\rightarrow Na^++e^-$

Hence, this statement is false.

Statement 4: The oxidation number for Hg(l) is 0.

Mercury is the 80th element of the periodic tale having electronic configuration of $[Xe]4f^{14}5d^{10}6s^2$

This element can show +1 or +2 oxidation states. Thus, this statement is false.

Statement 5: A reducing agent gains electrons.

Reducing agents are defined as the agents which reduces the other substance and itself gets oxidized. These agents undergoes oxidation reactions and oxidation reaction is defined as the reaction in which an atom looses its electrons.

Thus, this statement is false.

Statement 6: $Zn^{2+}$ is formed from the oxidation of Zn(s)

Oxidation reaction is defined as the reaction in which an atom looses its electrons. Here, oxidation state of the atom increases.

$X\rightarrow X^{n+}+ne^-$

Zinc is the 30th element and it will loose electrons to form zinc ion.

$Zn\rightarrow Zn^{2+}+2e^-$

Thus, this statement is True.

Hence, the correct statements are:

An oxidizing agent gains electrons and $Zn^{2+}$ is formed from the oxidation of Zn(s).

4 0

3 years ago

Read 2 more answers

Complete these structures by adding electron dots as needed.

LiRa [457]

This is hard to show but here is how you would determine these. NOTE each dot is an electron.
Question 1) 
F-H 
1) determine the valance electrons for each. F has 7 and H has 1 
2) one electron from both F and H form the bond "-" which means that you still have 6 electrons to place around F and none to place around H. Place the 6 in sets of 2 around the F 
.. 
F-H 
¨ 
Question 2) 

2) H-O-H 
H has 1 valence electron minus 1 used in the bond to O = 0 electrons to place 
H has 1 valence electron minus 1 used in the bond to O = 0 electrons to place 
O has 6 valence electrons minus 2 used in the bonds to the H's = 4 electrons to place 

H-O-H: place two dots above and below the oxygen 

Question 3) 
3) O=N----H : NOTE: a double bond requires O and N to share two of their electrons each 
O has 6 valence electrons minus 2 used in the bonds to N = 4 electrons to place 
N has 5 valence electrons minus 3 used in the bonds to O and H = 2 electrons to place 
H has 1 valence electron minus 1 used in the bond to N = 0 electrons to place 
place the 2 dots on top and bottom of oxygen. 
place 2 above the N

7 0

4 years ago