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Kisachek [45]
1 year ago
9

a student combined 45.3 ml of a 0.549 m calcium nitrate ca(no₃)₂ solution with 85.55 ml of a 1.321 m ca(no₃)₂ solution. calculat

e the concentration of the final solution.
Chemistry
1 answer:
RSB [31]1 year ago
6 0

When we combine the provided amounts of 0.549 M calcium nitrate Ca(NO3)2 solution and 1.321 M Ca(NO3)2 solution, the ultimate concentration of Ca(NO3)2 is 8.76 M.

<h3>What is molar concentration?</h3>

The amount of a solute present in one unit of a solution is known as its molar concentration. Mol/L, mol/dm3, or mol/m3 are its units. Molar concentration, also referred to as molarity, can be expressed with the letter M, or molar.

The amount of a substance in a specific volume of solution is known as its molarity (M). The number of moles of a solute per liter of a solution is known as molarity. The molar concentration of a solution is another name for molarity.

The ratio of the solute to solution amounts is known as concentration. A solute's molarity per liter of solution is measured using the unit of concentration.

To learn more about molarity here-

brainly.com/question/14469428

#SPJ4

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Explanation:

Heat released by the metal sample will be equivalent to the heat absorbed by  water.

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3150 c joules = 4002.0992 joules

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The fraction of the original amount remaining is closest to 1/128

<h3>Determination of the number of half-lives</h3>
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  • Time (t) = 4 weeks = 4 × 7 = 28 days
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n = t / t½

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<h3>How to determine the amount remaining </h3>
  • Original amount (N₀) = 100 g
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N = N₀ / 2ⁿ

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<h3>How to determine the fraction remaining </h3>
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Fraction remaining = N / N₀

Fraction remaining = 0.78125 / 100

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