3 years ago

How to convert 5.2 km to mm

Chemistry

1 answer:

ZanzabumX [31]3 years ago

4 0

5.2 km to mm.
1km = 1000m
= 5.2 * 1000m.
=5200 m. 1m = 1000mm

= 5200 * 1000mm
= 5200000 mm

You might be interested in

The mass of an object is 1,000 g. It has a volume of 100 mL. What is the density of the object? D= mass/volume

maxonik [38]

Answer:

10 g/ml

Explanation:

divide mass by volume means divide 1000 by 100 and your answer will be 10

4 0

3 years ago

If thermal energy (heat) must be added to a chemical reaction in order for the reaction to take place, the reaction is _________

Harlamova29_29 [7]

If thermal energy (heat) must be added to a chemical reaction in order for the reaction to take place, the reaction is endothermic.

7 0

3 years ago

What do all four animals have in common? cat worm spider crab

Free_Kalibri [48]

They are composed of cells

4 0

3 years ago

In which group of teh modern periodic table are there very reactive metals and very reactive non metals?

Rufina [12.5K]

Metals :-

Group 1A - Alkali metals ( highly reactive metals)

Non-metals :-

Group 17 - Halogens ( highly reactive non-metals )

5 0

3 years ago

A breeder nuclear reactor is a reactor in which nonfissile U-238 is converted into fissile Pu-239. The process involves bombardm

VARVARA [1.3K]

Answer: The nuclear equations for the given process is written below.

Explanation:

The chemical equation for the bombardment of neutron to U-238 isotope follows:

$_{92}^{238}\textrm{U}+n\rightarrow _{92}^{239}\textrm{U}$

Beta decay is defined as the process in which neutrons get converted into an electron and a proton. The released electron is known as the beta particle.

$_Z^A\textrm{X}\rightarrow _{Z+1}^A\textrm{Y}+_{-1}^0\beta$

The chemical equation for the first beta decay process of $_{92}^{239}\textrm{U}$ follows:

$_{92}^{239}\textrm{U}\rightarrow _{93}^{239}\textrm{Np}+_{-1}^0\beta$

The chemical equation for the second beta decay process of $_{93}^{239}\textrm{Np}$ follows:

$_{93}^{239}\textrm{Np}\rightarrow _{94}^{239}\textrm{Pu}+_{-1}^0\beta$

Hence, the nuclear equations for the given process is written above.

6 0

3 years ago