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2 years ago

9

What is an allotrope?

1 answer:

Lilit [14]2 years ago

3 0

A I think but idrk I just guess sorry if you get it wrong cause of me just be careful I could be wrong

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The reaction where heat is added is called? removed?

Harrizon [31]

Endothermic<span> Reaction??? </span>

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3 years ago

Anna notices that different types of clothing stick together when they are dried in an electric dryer. When the clothes are pull

horrorfan [7]

Answer:

Dry more clothes at the same time so that there is less room for electric forces.

Explanation:

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2 years ago

Read 2 more answers

How many moles of neon occupy a volume of 14.3 l at stp? how many moles of neon occupy a volume of 14.3 l at stp? 1.57 moles 0.6

andriy [413]

The number of neon moles that occupy a volume of 14.3 l at STP is calculated as follows

At STP 1 mole = 22.4 liters

what about 14.3 liters

by cross multiplication
= (1 mole x 14.3 l)/22.4 l =0.638 moles of neon

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3 years ago

prisoha [69]

A word equation is a written description of a chemical reaction.
All word equations start with the reactants.
Then, what comes next is the word "react to form."
Finally, the products of the equation are mentioned.
An example is,
Zinc and Hypochondriac acid react to form hydrogen gas and zinc chloride.

3 0

3 years ago

Calculate the pH of the following simple solutions:

IceJOKER [234]

Answer :

(1) pH = 1.27

(2) pH = 13.35

(3) The given solution is not a buffer.

Explanation :

<u>(1) 53.1 mM HCl</u>

Concentration of HCl = $53.1mM=53.1\times 10^{-3}M$

As HCl is a strong acid. So, it dissociates completely to give hydrogen ion and chloride ion.

So, Concentration of hydrogen ion= $53.1\times 10^{-3}M$

pH : It is defined as the negative logarithm of hydrogen ion concentration.

$pH=-\log [H^+]$

$pH=-\log (53.1\times 10^{-3})$

$pH=1.27$

<u>(2) 0.223 M KOH</u>

Concentration of KOH = 0.223 M

As KOH is a strong base. So, it dissociates completely to give hydroxide ion and potassium ion.

So, Concentration of hydroxide ion= 0.223 M

Now we have to calculate the pOH.

$pOH=-\log [OH^-]$

$pOH=-\log (0.223)$

$pOH=0.65$

Now we have to calculate the pH.

$pH+pOH=14\\\\pH=14-pOH\\\\pH=14-0.65=13.35$

<u>(3) 53.1 mM HCl + 0.223 M KOH</u>

Buffer : It is defined as a solution that maintain the pH of the solution by adding the small amount of acid or a base.

It is not a buffer because HCl is a strong acid and KOH is a strong base. Both dissociates completely.

As we know that the pH of strong acid and strong base solution is always 7.

So, the given solution is not a buffer.

5 0

2 years ago