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oksano4ka [1.4K]
3 years ago
13

Who is ACP pradyuman

Engineering
2 answers:
lara31 [8.8K]3 years ago
5 0
ACP Pradyuman is a fictional character from Indian Television show CID. The character is portryaed by actor Shivaji Satam.
Kamila [148]3 years ago
4 0

Answer:

he is the chief officer of crime invistegating department.

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Column arrays: Transpose a row array Construct a row array countValues with elements 1 to endValue, using the double colon opera
White raven [17]

Answer:

Matlab code with step by step explanation and output results are given below

Explanation:

We have to construct a Matlab function that creates a row vector "countValues" with elements 1 to endValue. That means it starts from 1 and ends at the value provided by the user (endValue).  

function countValues = CreateArray(endValue)

% Here we construct a row vector countValues from 1:endValue

     countValues = 1:endValue;

% then we transpose this row vector into column vector

     countValues = countValues';

 end

Output:

Calling this function with the endValue=11 returns following output

CreateArray(11)

ans =

    1

    2

    3

    4

    5

    6

    7

    8

    9

   10

   11

Hence the function works correctly. It creates a row vector then transposes it and makes it a column vector.

7 0
3 years ago
You should be extra careful during the hours of sunrise, sunset, and nighttime because _____. A. of increased law enforcement ac
torisob [31]

Answer:

B, its the only valid answer

5 0
4 years ago
A manufacturing company has decided to be carbon free by 2030.
k0ka [10]

Answer:

company should focus on their goals

4 0
3 years ago
A bar having a length of 5 in. and cross-sectional area of 0.7 i n . 2 is subjected to an axial force of 8000 lb. If the bar str
barxatty [35]

Answer:

E=1.969 × 10¹¹ Pa

Explanation:

The formula to apply is;

E=F*L/A*ΔL

where

E=Young modulus of elasticity

F=Force in newtons

L=Original length in meters,m

A=area in square meters m²

ΔL= Change in length in meters,m

Given

F= 8000 lb = 8000*4.448 =35584 N

L= 5 in = 0.127 m

A= 0.7 in² =0.0004516 m²

ΔL = 0.002 in = 5.08e-5 m

Applying the formula

E=(35584 * 0.127)/(0.0004516*5.08e-5 )

E=1.969 × 10¹¹ Pa

8 0
4 years ago
Consider the base plate of an 800-W household iron with a thickness of L = 0.6 cm, base area of A =160 cm2, and thermal conducti
ratelena [41]

Given-

Power, P = 800W

Thickness, L = 0.6cm

Area, A = 160cm²

Thermal conductivity, k = 60W/mK

The heat conduction would be

\frac{d^2T}{dx^2} + \frac{d^2T}{dy^2} + \frac{d^2T}{dz^2} + \frac{e(gen)}{k}  = \frac{1}{\alpha } \frac{dT}{dt}

Except \frac{d^2T}{dx^2} all the values are 0.

Therefore,

\frac{d^2T}{dx^2} = 0

Thus, the boundary conditions here would be

1. Q_x_=_0 = -kA \frac{dT (0)}{dx} = Q_o

2. T(L) = T_L

4 0
4 years ago
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