Answer:
Explanation:
B. you would grab the plug closest to the outlet
Answer:
Head loss=0.00366 ft
Explanation:
Given :Water flow rate Q=0.15
= 6 inch=0.5 ft
=2 inch=0.1667 ft
As we know that Q=AV
So
=0.687 ft/sec
We know that Head loss due to sudden contraction
If nothing is given then take K=0.5
So head loss
=0.00366 ft
So head loss=0.00366 ft
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Answer:
the critical flaw length is 10.06 mm
Explanation:
Given the data in the question;
plane strain fracture toughness = 92 Mpa√m
yield strength σ = 900 Mpa
design stress is one-half of the yield strength ( 900 Mpa / 2 ) 450 Mpa
Y = 1.15
we know that;
Critical crack length = 1/π( / Yσ )²
we substitute
= 1/π( 92 Mpa√m / (1.15 × 450 Mpa )²
= 1/π( 92 Mpa√m / (517.5 Mpa )²
= 1/π( 0.177777 )²
= 1/π( 0.03160466 )
= 0.01006 m = 10.06 mm
Therefore, the critical flaw length is 10.06 mm
{ = ( 10.06 mm ) > 3 mm
The critical flow is subject to detection
Answer:
False
Explanation:
The two most important fields of expertise for their career were not defined as architecture and mathematics by architects.
It offers expertise and expertise to architects and engineers that can not be gained by practicing alone.