1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
tatiyna
2 years ago
9

a rectangle has a length of 15 inches less than 5 times it’s width. If the area of the rectangle is 2750 square inches. what is

the length of the rectangle
Mathematics
1 answer:
irakobra [83]2 years ago
4 0

let L = length and let W = width.

Use the equations 2L + 2W = 2750

and L = 5W + 15

Then do the steps as follows -

1. Plug the equation for what L equals into the first equation

2(5W+15) + 2W = 2750

2. Then distribute the 2

10W + 30 + 2W = 2750

3. Then add like terms

12W + 30 = 2750

4. Then subtract 30 from both sides

12W = 2720

5. Divide by 12 on both sides

W = 226.67

6. Then plug that into the second equation

L = 5(226.67) + 15

L = 1148.35 should be the answer


You might be interested in
Davis predicts that if he spins the spinner another 20
alukav5142 [94]

Answer:

d

Step-by-step explanation:

or if your on online school the last one

No. The frequencies and probabilities for red and green segments might change in the next experiment.

5 0
3 years ago
What are the domain and range of the function below?<br> !!!!!!
Diano4ka-milaya [45]

Answer:

we need to see the whole graph to determine the domain and range please

Step-by-step explanation:

8 0
3 years ago
What are the total amount of choices possible if an individual is to create a 4 digit password using the digits 0 through 9 incl
qwelly [4]

9000 ways to create 4-digit passwords using digits from 0 to 9 that the first character can't be 0, but not using the digit 0 as the first character.

We have to see how many different 4-digit passwords we can create by using digits from 0 to 9, such that the first character can't be 0.

<h3>What is the combination?</h3>

Each of the different groups or selections can be formed by taking some or all of a number of objects, irrespective of their arrangments is called a combination.

Here we have 4 selections.

Now let's find the number of options for each of these:

First character = 9 options {1, 2, 3, 4, 5, 6, 7, 8, 9, 10}

Second character = 10 options {0, 1, 2, 3, 4, 5, 6, 7, 8, 9, 10}

Third character = 10 options {0, 1, 2, 3, 4, 5, 6, 7, 8, 9, 10}

Fourth character = 10 options {0, 1, 2, 3, 4, 5, 6, 7, 8, 9, 10}

The total number of different combinations is just the product of these 4 numbers:

C = 9×10×10×10 = 9,000

So, we can conclude that the correct option is D.

If you want to learn more about combinations visit here;

brainly.com/question/2280026

4 0
2 years ago
Read 2 more answers
Identify the graph of xy=-8 for theta=pi/4 and write and equation of the translated or rotated graph in general form.
eduard

Answer:

B

Step-by-step explanation:

I hope this helps!

4 0
3 years ago
Read 2 more answers
What is the decimal for 4 2/3?
muminat
4.67 would be a rounded answer. Really it's 4.666666666666666666 (the 6 go on forever) but we can't write that out.
8 0
3 years ago
Other questions:
  • Solve 75=125 (0.8)t^
    5·2 answers
  • 2x+4x=3x+1 how do you do this
    8·1 answer
  • 5726 similar to 5672
    9·2 answers
  • Which of the following could be an example of a function with a domain
    14·2 answers
  • Lin took 75 boxes of carrots and 80 boxes of potatoes to the market. She sold 68 boxes of carrots and 71 boxes of potatoes. How
    6·2 answers
  • Which of the following sets contains only rational numbers?
    8·1 answer
  • What is the surface area of the cylinder with height 5 mi and radius 2 mi? Round your
    10·1 answer
  • Find the equation of the line <br> PLEASE HELP
    10·2 answers
  • Please help me and show work on a piece of paper​
    9·1 answer
  • Answerr this question right and i will give u brainlist
    5·2 answers
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!