Answer:
-37/6
Step-by-step explanation:
Hello :
<span> sin 2x = sin x and 0 ≤ x ≤ 2π.
all solutions :
2x= x +2k</span>π or x= π -x +2kπ ..... k in : Z
x = 2kπ or : x = π/2 + kπ
but :
<span>0 ≤ x ≤ 2π
</span><span>all values of x such that sin 2x = sin x and 0 ≤ x ≤ 2π are :
</span>k = 0 : x=0 , x= π/2
k=1 : x=2 π , x=3π/2
Answer:
36/7
Step-by-step explanation:
{(6+3)/(-5-2)}(-4)
36/7
Answer:
Step-by-step explanation:
11
Answer:
Step-by-step explanation:
1) The center lies on the vertical line x = -5 and the the circle is tangent to (touches in one place only) the y-axis. Thus, the radius is 5.
2) Starting with (x - h)^2 + (y - k)^2 = r^2 and comparing this to the given
(x - 4)^2 + (y + 3)^2 = 6^2
we see that h = 4, k = -3 and r = 6. The center is at (4, -3) and the radius is 6.
3) Notice that A and B have the same x-coordinate, x = 15. The center of the circle is thus (15, -2), where that -2 is the halfway point between the two given points in the vertical direction. Arbitrarily choose A(15, 4) as one point on the circle. Then the equation of this circle is
(x - 4)^2 + (y + 3)^2 = r^2 = 6^2, where the 6 is one half of the vertical distance between A(15, 4) and B(15, -8) (which is 12).
