Answer:
Step-by-step explanation:
A possible word problem for 3x+10 ≤75 could be
Mat has $75 dollars saved in his wallet and wants to use it for go carts. Knowing that the entrance to the park is $10, and each time around the go cart course is $3 what is the maximum times he can go around?
3x+10 ≤ 75, subtract 10 from both sides
3x ≤ 75-10, divide both sides by 3
x ≤ 65/3
or x ≤ 21.(6)
So it can go around 21 times the most.
<span>–10, –7.5, –5, –2.5, …
Is defined by the formula because the next term can be obtained by adding 2.5 to the current one.</span>
Part A:
Given that <span>the mattress is sold for 50% off of the retail price, let the retail price of the mattress be x, then
50% of x = 1200
⇒ 0.5x = 1200
⇒ x = 1200 / 0.5 = 2400
Therefore, </span><span>the retail price of the mattress, before the discount is $2,400.
Part B:
Given that </span><span>the store marks up the retail price to 150% of the wholesale price. Let the whole sale price be p, then
(100% + 150%) of p = 2400
250% of p = 2400
2.5p = 2400
p = 2400 / 2.5 = 960.
Therefore, </span><span>the wholesale price, before the markup was $960</span>
Answer:
The probability that there are 3 or less errors in 100 pages is 0.648.
Step-by-step explanation:
In the information supplied in the question it is mentioned that the errors in a textbook follow a Poisson distribution.
For the given Poisson distribution the mean is p = 0.03 errors per page.
We have to find the probability that there are three or less errors in n = 100 pages.
Let us denote the number of errors in the book by the variable x.
Since there are on an average 0.03 errors per page we can say that
the expected value is, 
= E(x)
= n × p
= 100 × 0.03
= 3
Therefore the we find the probability that there are 3 or less errors on the page as
P( X ≤ 3) = P(X = 0) + P(X = 1) + P(X=2) + P(X=3)
Using the formula for Poisson distribution for P(x = X ) = 
Therefore P( X ≤ 3) = 
= 0.05 + 0.15 + 0.224 + 0.224
= 0.648
The probability that there are 3 or less errors in 100 pages is 0.648.
The equation for a trapezoid is A = a+b all over 2 times h
So, you would simply substitute.
A=15
B=12
H=8
15+12/2 (8)=
27/2 (8)=
13.5 (8)=
108.
