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Zanzabum
3 years ago
5

Help please I beg of the ​

Mathematics
1 answer:
Anika [276]3 years ago
7 0

Answer:

1 would be on 1.4 so before 1.5 on the line

2 would be on around 4.1 so after 4.0 by a little

3 would be on 3.3 so kind of in the middle of 3.0 and 3.5

4 would be on 2.8 so before 3.0

5 is on 2.2 so a little after 2.0

6 would be just a little more than 5 around 5.09

11 is E

12 is A

13 is D

14 is C

15 is B

16 is B

17 is A

18 is D

19 is C

20 is E

All you have to do is find the square root through a calculator then round your answer and estimate where it would go on the line. Hope this helped

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Using Postulates and/or Theorems learned in Unit 1, determine whether PRQ MRN.
Umnica [9.8K]

Answer:

RM / RP = 10/18 = 5/9

RN/RQ = 7/21 = 1/3

Since the two ratios are not the same, triangle PRQ is not similar to triangle MRN.

Step-by-step explanation:

5 0
2 years ago
Can someone help me with system of equations?
nignag [31]
2x + y = 350
x + 2y = 475 
3x + 3y = 825
x + y = 275
x = 275 - y 
(plug back into first equation) 
2(275 - y) + y = 350
550 - 2y + y = 350 
550 - y = 350
-y =-200 or y = $200 (dog)
therefore, x = $75 (cats)
Check
2(75) + 200 = 350
75 + 400 = 475 
HAPPINESS! :)
3 0
3 years ago
<img src="https://tex.z-dn.net/?f=%20%5Crm%20%5Cint_%7B0%7D%5E%7B%20%20%5Cpi%20%7D%20%5Ccos%28%20%5Ccot%28x%29%20%20%20%20-%20%2
Nikolay [14]

Replace x with π/2 - x to get the equivalent integral

\displaystyle \int_{-\frac\pi2}^{\frac\pi2} \cos(\cot(x) - \tan(x)) \, dx

but the integrand is even, so this is really just

\displaystyle 2 \int_0^{\frac\pi2} \cos(\cot(x) - \tan(x)) \, dx

Substitute x = 1/2 arccot(u/2), which transforms the integral to

\displaystyle 2 \int_{-\infty}^\infty \frac{\cos(u)}{u^2+4} \, du

There are lots of ways to compute this. What I did was to consider the complex contour integral

\displaystyle \int_\gamma \frac{e^{iz}}{z^2+4} \, dz

where γ is a semicircle in the complex plane with its diameter joining (-R, 0) and (R, 0) on the real axis. A bound for the integral over the arc of the circle is estimated to be

\displaystyle \left|\int_{z=Re^{i0}}^{z=Re^{i\pi}} f(z) \, dz\right| \le \frac{\pi R}{|R^2-4|}

which vanishes as R goes to ∞. Then by the residue theorem, we have in the limit

\displaystyle \int_{-\infty}^\infty \frac{\cos(x)}{x^2+4} \, dx = 2\pi i {} \mathrm{Res}\left(\frac{e^{iz}}{z^2+4},z=2i\right) = \frac\pi{2e^2}

and it follows that

\displaystyle \int_0^\pi \cos(\cot(x)-\tan(x)) \, dx = \boxed{\frac\pi{e^2}}

7 0
1 year ago
A potato chip company makes potato chips in two flavors, Regular and Salt &amp; Vinegar. Riley is a production manager for the c
tiny-mole [99]

Answer:

(a) H0:μ1=μ2; Ha:μ1≠μ2, which is a two-tailed test.

Step-by-step explanation:

We formulate the

H0: μ1=μ2; null hypothesis that the two means are equal and alternate hypothesis that the two mean are not equal.

Ha:μ1≠μ2 Two tailed test

Test statistic used is

t= x1`-x2` / s√n as the variances are equal and sample size is same

T value for 9 degrees of freedom for two tailed test at α = 0.05 is 2.26

P- value for t test for 9 degrees of freedom is 0.125 from the table.

Hence only a is correct .

4 0
2 years ago
Tammy deposited $520 in the bank account that earns simple interest every year after 5 years she had earned $156 and interest if
aleksley [76]

Answer:

6%.

Step-by-step explanation:

We have been given that Tammy deposited $520 in the bank account that earns simple interest every year after 5 years she had earned $156.

To find the interest rate we will use simple interest formula.

I=P*r*T

I= Interest.

P= Principal amount.

r=Annual interest rate (in decimal form).

T= Time in years.

We have been given that I=156, T=5, P=520

Upon substituting our values in above formula we will get,

156=520*r*5

156=2600r

r=\frac{156}{2600}

r=0.06

Let us multiply 0.06 by 100 to convert annual interest rate in percentage.

0.06*100=6 \text{ percent}

Therefore, the annual interest rate was 6%.

6 0
3 years ago
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