All categories

2 years ago

Solve for b. Help pls thank u !!!!

Mathematics

1 answer:

Nadusha1986 [10]2 years ago

5 0

Step-by-step explanation:

3b - 3.76 = 1.34

3b = 3.76+ 1.34

3b = 5.1

b= 5.1/3

= 1.7

You might be interested in

If x and y vary directly and x=25 when y=100 find x when y=24.<br> PLEASE HELP FASTTTTTTT

Veseljchak [2.6K]

Answer:

x = 6

Step-by-step explanation:

Given that x and y vary directly then the equation relating them is

y = kx ← k is the constant of variation

To find k use the condition x = 25 when y = 100 , then

100 = 25k ( divide both sides by 25 )

4 = k

y = 4x ← equation of variation

When y = 24 , then

24 = 4x ( divide both sides by 4 )

6 = x

6 0

2 years ago

I need help with both of these questions please

tankabanditka [31]

Answer:

$\frac{22}{30} = \frac{11}{15}$

and

$\frac{176}{7} = 25 \frac{1}{7}$

Step-by-step explanation:

First make all the fractions into improper fractions

$1\frac{5}{6} = \frac{11}{6} \\\\2\frac{1}{2} = \frac{5}{2} \\\\3\frac{1}{7} = \frac{22}{7}$

After doing that put them back into the problems

Problem 1)

$1\frac{5}{6}$ ÷ $2\frac{1}{2}$ , plug in the improper fractions

$\frac{11}{6}$ ÷ $\frac{5}{2}$

to divide, you need to flip the second fraction and multiply

$\frac{11}{6}$ · $\frac{2}{5}$ = $\frac{22}{30}$

then reduce

$\frac{22}{30} = \frac{11}{15}$

Problem 2)

$3\frac{1}{7}$ ÷ $\frac{1}{8}\\$

Plug in improper fraction

$\frac{22}{7}$ ÷ $\frac{1}{8}\\$

Then flip second fraction and multiply

$\frac{22}{7}$ · $\frac{8}{1}$

Multiply

$\frac{176}{7}$

Reduce, or make it a mixed number

$\frac{176}{7} = 25 \frac{1}{7}$

3 0

2 years ago

Given points A(-1, -2) and B(2, 4) where AP: BP=1:2, find the locus of point P.

koban [17]

Answer:

$x^2 + 4x + y^2 +8y = 0$

Step-by-step explanation:

Given

$A = (-1,-2)$

$B = (2,4)$

$AP:BP = 1 : 2$

Required

The locus of P

$AP:BP = 1 : 2$

Express as fraction

$\frac{AP}{BP} = \frac{1}{2}$

Cross multiply

$2AP = BP$

Calculate AP and BP using the following distance formula:

$d = \sqrt{(x - x_1)^2 + (y - y_1)^2}$

So, we have:

$2 * \sqrt{(x - -1)^2 + (y - -2)^2} = \sqrt{(x - 2)^2 + (y - 4)^2}$

$2 * \sqrt{(x +1)^2 + (y +2)^2} = \sqrt{(x - 2)^2 + (y - 4)^2}$

Take square of both sides

$4 * [(x +1)^2 + (y +2)^2] = (x - 2)^2 + (y - 4)^2$

Evaluate all squares

$4 * [x^2 + 2x + 1 + y^2 +4y + 4] = x^2 - 4x + 4 + y^2 - 8y + 16$

Collect and evaluate like terms

$4 * [x^2 + 2x + y^2 +4y + 5] = x^2 - 4x + y^2 - 8y + 20$

Open brackets

$4x^2 + 8x + 4y^2 +16y + 20 = x^2 - 4x + y^2 - 8y + 20$

Collect like terms

$4x^2 - x^2 + 8x + 4x + 4y^2 -y^2 +16y + 8y + 20 - 20 = 0$

$3x^2 + 12x + 3y^2 +24y = 0$

Divide through by 3

$x^2 + 4x + y^2 +8y = 0$

3 0

2 years ago

Find the first four terms of the sequence given by the following.<br> an=51 + (n-1).8, n=1, 2, 3...

pav-90 [236]

Answer:

Step-by-step explanation:

a1 = 51 + (1 -1 ) * 0.8

a1 = 51

a2 = 51 + (2 - 1)*0.8

a2 = 51 + 0.8

a2 = 51.8

a3 = 51 + (3 - 1)*0.8

a3 = 51 + 2*0.8

a3 = 51 + 1.6

a3 = 52.6

a4 = 51 + (4 - 1)*0.8

a4 = 51 + 2.4

a4 = 53.4

5 0

2 years ago

Can someone help me with this please

krek1111 [17]

I think the answer is 60
idk

7 0

2 years ago