Answer:
The dimensions of the rectangle = 60ft by 107ft
Where 60 ft = Width of the playing field
107ft = Length of the playing field
Step-by-step explanation:
A playing field is Rectangular is shape, hence,
The formula for Perimeter of a rectangle = 2(L + W)
P = 334 ft
L = 47 + W
W = W
Hence we input these values in the formula and we have:
334 = 2(47 + W + W)
334 = 2(47 + 2W)
334 = 94 + 4W
334 - 94 = 4W
240 = 4W
W = 240/4
W = 60
There fore, the width of this playing field = 60 ft
The length of this rectangle is calculated as:
47 + W
47 + 60
= 107 ft
The length of this playing field = 107ft
Therefore the dimensions of the rectangle = 60ft by 107ft
Answer:
9) C. 35 + 0.12x = 44.36
10) B
11) A. 32
Step-by-step explanation:
9)
44.36 is the TOTAL so the equations have to EQUAL it.
PER mile means it's a variable so it's 0.12x:
35 is a constant so there's no variable attached:
35 + 0.12x = 44.36
10)
B because you have to cancel the y values and to do that, you multiply the 1st equation by 3.
11)
0.1x + 0.25(46 - x) = 6.70
0.1x + 11.5 - 0.25x = 6.7
-0.15x = 6.7 - 11.5
-0.15x = -4.8
x = 32
Answer:
69.1 cm
Step-by-step explanation:
Circumference of a circle
c = 2πr
Half of that would be a semi-circle
c = πr
c = π * 22
c = 69.115038379
Rounded
69.1 cm
Y = (1/5)x -2
for a perpendicular line, you make the slope the reciprocal of the other equation
