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8_murik_8 [283]
2 years ago
8

Last year, 140 people in a community had cell phones. This year, the number of people in the community with cellphones has incre

ased by 65%.
A. What is the percent increase

B. What is the change in thr number of people ith cellphones?

C. How many peope in the community have cellphones this year?
Mathematics
1 answer:
kiruha [24]2 years ago
5 0

a 65%

b 91

c 231

now im typing so it will let me answer

ssssssssssssssssssssssssssss

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EM Company produces two types of laptop computer bags. The regular version requires $32 in capital and 4 hours of labor and sell
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Answer:

Step-by-step explanation:

Given that EM company produces two types of laptop computer bags.

Let regular version produced be R and deluxe version be D

Total capital required

= 32R+38D\leq 2100

Total labor hours required

=4R+6D\leq 280

Sales revenue = 46R+55D

Solving the two constraints we have

10D \leq 140

D can be atmost 14 and hence R can be 49

Otherwise if D is made 0, R = 65 maximum

If R is made 0, D maximum is 46

Thus corner points are (65,0) (0.,46) or (49,14)

Sales revenue for (65,0) = 2990

(0,46) is 2530

(49,14) is 3024

Maximum when R =14 and D is 49

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Seven less than eight times a number is -12
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Answer:

19/8

Step-by-step explanation:

8x-7=-12

8x=19

x=19/8

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Robert went to the grocery store and purchased cans of soup and frozen dinners. each can of soup has 300 mg of sodium and each f
Paraphin [41]

There are 9 cans of soup and 5 cans of frozen dinner.

The variables used for soup and frozen dinner are x and y respectively.

Step-by-step explanation:

Let,

Soup = x

Frozen Dinner = y

According to given statement of sodium;

300x + 500y = 5200 eqn 1

And,

x + y = 14 eqn 2

Multiplying\ equation\ 2\ with\ 300\\300(x+y=14)\\300x+300y=4200\ Eqn 3\\

Subtracting Eqn 3 from Eqn 1;

(300x+500y)-(300x+300y)=5200-4200\\300x+500y-300x-300y=1000\\200y=1000\\y=\frac{1000}{200} \\y=5

Putting value of y in Eqn 1;

300x+500(5)=5200\\300x+2500=5200\\\\Subtracting\ 2500\ from\ both\ sides\ \\300x+2500-2500=5200-2500\\300x=2700\\x=\frac{2700}{300} \\x=9

There are 9 cans of soup and 5 cans of frozen dinner.

The variables used for soup and frozen dinner are x and y respectively.

Keywords: Variables, linear equations, subtraction.

Learn more about linear equations at;

  • brainly.com/question/5047646
  • brainly.com/question/5048216

#LearnwithBrainly

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