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matrenka [14]
3 years ago
11

Hich pairs of fractions include a fraction equivalent to 12 and a fraction equivalent to 25? Select each correct answer. 510 and

48 13 and 412 510 and 410 48 and 410
Mathematics
1 answer:
Scorpion4ik [409]3 years ago
3 0

Answer:

4/8 and 4/10

Step-by-step explanation:

Required

Select which option is equivalent to 1/2 and 2/5

Option (a): 5/10 and 4/8

Simplify 5/10

5/10 = 1/2

Simplify 4/8

4/8 = 1/2

This is not true

Option (b): 1/3 and 4/12

1/3 is not equivalent to 1/2 or 2/5.

So, this is not true

Option (c): 4/12 and 5/10

Simplify 4/12

4/12 = 1/3

1/3 is not equivalent to 1/2 or 2/5.

So, this is not true

Option (d): 4/8 and 4/10

Simplify 4/8

4/8 = 1/2

Simplify 4/10

4/10 = 2/5

Hence, (d) is true

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What is the answer <br> How do you solve this
Talja [164]

The term for this sequence is 2.

It's an easy pattern!..

The second term is two times two.

The third term is two times three and so on..

4 0
3 years ago
N = x + y - n = 5<br> and part two<br> x = u + v = o<br><br> whats the answer?
Colt1911 [192]
Just substitute the value of x from second equation into first equation:
N = x + y - n = 5
N = u + v  + y - n = 5
N = 0 + y - n = 5

In short, N would be equal to y - n which is still equal to 5

Hope this helps!
8 0
2 years ago
Please !!!!!! Help me
PtichkaEL [24]

Answer:

a. 1 b. 3/5 or 60%

Step-by-step explanation:

number of favourable events/number of total events

3x/5x = 3/5

5 0
3 years ago
How do I solve this and what kind of formula is it?
soldier1979 [14.2K]

Answer:

160

Step-by-step explanation:

The measure of an arc is always twice the degree of the corresponding angle inside the circle. For example, the measure of arc DC is just double the measure of angle DOC; angle DOC is 44 degrees, so arc DC must be 88 degrees.

Angle COB is 80 degrees, so arc CB is 160 degrees.

5 0
3 years ago
What is the equation of the line that passes through the points (5, 3) and (-3,-1)?
Liono4ka [1.6K]

Answer:

y=1/2x+1/2

m=1/2

Step-by-step explanation:

You want to find the equation for a line that passes through the two points:

(5,3) and (-3,-1).

First of all, remember what the equation of a line is:

y = mx+b

Where:

m is the slope, and

b is the y-intercept

First, let's find what m is, the slope of the line...

The slope of a line is a measure of how fast the line "goes up" or "goes down". A large slope means the line goes up or down really fast (a very steep line). Small slopes means the line isn't very steep. A slope of zero means the line has no steepness at all; it is perfectly horizontal.

For lines like these, the slope is always defined as "the change in y over the change in x" or, in equation form:

So what we need now are the two points you gave that the line passes through. Let's call the first point you gave, (5,3), point #1, so the x and y numbers given will be called x1 and y1. Or, x1=5 and y1=3.

Also, let's call the second point you gave, (-3,-1), point #2, so the x and y numbers here will be called x2 and y2. Or, x2=-3 and y2=-1.

Now, just plug the numbers into the formula for m above, like this:

m=

-1 - 3 over

-3 - 5

or...

m=

-4 over

-8

or...

m=1/2

So, we have the first piece to finding the equation of this line, and we can fill it into y=mx+b like this:

y=1/2x+b

Now, what about b, the y-intercept?

To find b, think about what your (x,y) points mean:

(5,3). When x of the line is 5, y of the line must be 3.

(-3,-1). When x of the line is -3, y of the line must be -1.

Because you said the line passes through each one of these two points, right?

Now, look at our line's equation so far: y=1/2x+b. b is what we want, the 1/2 is already set and x and y are just two "free variables" sitting there. We can plug anything we want in for x and y here, but we want the equation for the line that specfically passes through the two points (5,3) and (-3,-1).

So, why not plug in for x and y from one of our (x,y) points that we know the line passes through? This will allow us to solve for b for the particular line that passes through the two points you gave!.

You can use either (x,y) point you want..the answer will be the same:

(5,3). y=mx+b or 3=1/2 × 5+b, or solving for b: b=3-(1/2)(5). b=1/2.

(-3,-1). y=mx+b or -1=1/2 × -3+b, or solving for b: b=-1-(1/2)(-3). b=1/2.

See! In both cases we got the same value for b. And this completes our problem.

The equation of the line that passes through the points

(5,3) and (-3,-1)

is

y=1/2x+1/2

7 0
3 years ago
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