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3 years ago

6

The Bengals football team scored 2 touchdowns for 6 points each, one extra point, and 3 field goals for 3 points each. The Raven

s scored an equal number of points, except for an additional field goal. What was the final score for the game?

1 answer:

Yanka [14]3 years ago

4 0

bangles scored 22 pts but don't know how much the ravens scored

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Select the correct answer. What is the value of c, correct to one decimal place? A. 4.6 B. 3.2 C. 2.8 D. 1.2

Schach [20]

The answer I think is 0.28

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2 years ago

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F has 10 more marbles than I. Both boys have 15 marbles combined. How many marbles does each boy have?

olganol [36]

Answer:

F has 10 marbles and I has 5 marbles.

Step-by-step explanation:

First, I subtracted 10 from 15 since F has 10 more marbles than I. When I subtracted I got 5.

Hope this helps!!!!

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2 years ago

What is the probability of not drawing a card 6 or greater from a regular deck of cards?

Mamont248 [21]

Ok so there are 52 cards in a deck if you take all the cards that have the number 6 which is only 4 cards so 52-4 = 48 cards without any 6 so the ratio is 48/52
chances.

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2 years ago

Convert 3.92 into mixed fraction in simplest form

anygoal [31]

$3.92=3+0.92=3+\frac{92}{100}=3+\frac{92:4}{100:4}=3+\frac{23}{25}=\boxed{3\frac{23}{25}}$

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2 years ago

A large cube has a volume of 1 cubic unit. A small cube has a volume of 1 27 of a cubic unit. What is the difference between the

ExtremeBDS [4]

Given:

Volume of Large cube = 1 cubic unit

Volume of small cube = $\dfrac{1}{27}$ cubic unit

To find:

The difference between the edge length of the large cube and the edge length of the small cube.

Solution:

Let the edges of large and small cubes are $a_1$ and $a_2$ respectively.

We know that, volume of a cube is

$V=(edge)^3$

Volume of Large cube = 1 cubic unit

$(a_1)^3=1$

Taking cube root on both sides, we get

$a_1=1$

So, edge of large cube is 1 unit.

Volume of small cube = $\dfrac{1}{27}$ cubic unit

$(a_2)^3=\dfrac{1}{27}$

Taking cube root on both sides, we get

$a_2=\dfrac{1}{3}$

So, edge of large cube is $\dfrac{1}{3}$ unit.

Now, difference between them is

$d=a_1-a-2$

$d=1-\dfrac{1}{3}$

$d=\dfrac{3-1}{3}$

$d=\dfrac{2}{3}$

Therefore, the difference between the edge length of the large cube and the edge length of the small cube is $\dfrac{2}{3}$ unit.

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2 years ago