Question

A student stands 20 m away from the foot

Answer 1

Answer:

Height of tree is $\approx$ 15 m.

Step-by-step explanation:

Given that student is 20 m away from the foot of tree.

and table is 1.5 m above the ground.

The angle of elevation is: 34°28'

Please refer to the attached image. The given situation can be mapped to a right angled triangle as shown in the image.

AB = CP = 20 m

CA = PB = 1.5 m

$\angle C$ = 34°28' = 34.46°

To find TB = ?

we can use trigonometric function tangent to find TP in right angled $\triangle TPC$

$tan \theta = \dfrac{Perpendicular}{Base}\\tan C= \dfrac{PT}{PC}\\\Rightarrow tan 34.46^\circ = \dfrac{PT}{20}\\\Rightarrow PT = 20 \times 0.686 \\\Rightarrow PT = 13.72\ m$

Now, adding PB to TP will give us the height of tree, TB

Now, height of tree TB = TP + PB

TB = 13.72 + 1.5 = 15.22 $\approx$ 15 m