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vampirchik [111]
4 years ago
15

A student stands 20 m away from the foot

Mathematics
1 answer:
Ostrovityanka [42]4 years ago
7 0

Answer:

Height of tree is \approx <em>15 m.</em>

<em></em>

Step-by-step explanation:

Given that student is 20 m away from the foot of tree.

and table is 1.5 m above the ground.

The angle of elevation is: 34°28'

Please refer to the attached image. The given situation can be mapped to a right angled triangle as shown in the image.

AB = CP = 20 m

CA = PB = 1.5 m

\angle C = 34°28' = 34.46°

To find TB = ?

we can use trigonometric function tangent to find TP in right angled \triangle TPC

tan \theta = \dfrac{Perpendicular}{Base}\\tan C= \dfrac{PT}{PC}\\\Rightarrow tan 34.46^\circ = \dfrac{PT}{20}\\\Rightarrow PT = 20 \times 0.686 \\\Rightarrow PT = 13.72\ m

Now, adding PB to TP will give us the height of tree, TB

Now, height of tree TB = TP + PB

TB = 13.72 + 1.5 = 15.22 \approx <em>15 m</em>

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Data given and notation  

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