πAnswer:
Therefore, the area of a sector of a circle would be 13.5π square units.
Step-by-step explanation:
Given
mi
The area of a sector of a circle is:
A = π r² Ф/360
A = π (9)² 60/360
A = π 81 * 1/6
A = 13.5π square units
Therefore, the area of a sector of a circle would be 13.5π square units.
Answer:
Step-by-step explanation:
2{5x²-15+(-9xy²)}-(2y²+4x-xy²)+3x²
=2{5x²-15-9xy²}-(2y²+4x-xy²)+3x²
=10x²-30-18xy²-2y²-4x+xy²+3x²
=13x²-2y²-17xy²-4x-30
Plug
into the equation of the ellipsoid:

Complete the square:

Then the intersection is such that


which resembles the equation of a circle, and suggests a parameterization is polar-like coordinates. Let



(Attached is a plot of the two surfaces and the intersection; red for the positive root
, blue for the negative)