Commonsense you do math in your mind
Complete question :
Mr. Nelson lost one of his students' test papers. He knows that the other 4 students scored as follows: 60, 62, 56, 57. He also knows that the average score is 59.2. What is the score on the missing paper?
Answer:
61
Step-by-step explanation:
Given the following :
Total number of students = 4 + 1 missing = 5
Score on the four avaliable papers = 60, 62, 56, 57
Average score of the 5 papers = 59.2
Score on missing paper :
Sum of each score / number of papers
Sum of each score = sum of available scores + missing score
Let missing score = m
(60 + 62 + 56 + 57 + m) = 235 + m
Recall:
Average = total sum / number of observations
Hence,
59.2 = (235 + m) / 5
59.2 × 5 = 235 + m
296 = 235 + m
m = 296 - 235
m = 61
Missing score = 61
Answer:
9 sq. units
Step-by-step explanation:
dimensions of rectangle are (7-3),(8-3)
or 4,5
area of rectangle=4×5=20
area of bottom Δ=1/2×4×2=4
area of top Δ=1/2×3×3=9/2
area of right triangle=1/2 ×5×1=5/2
area of Δ HIJ=20-(4+9/2+5/2)
=20-(4+14/2)
=20-(4+7)
=9 sq. units.
or area of triangle =1/2
| 3 5 |
| 7 3 |
|6 8 |
|3 5 |
=1/2[(9-35)+(56-18)+(30-24)]
=1/2[-26+38+6]
=1/2[-26+44]
=1/2(18)
=9 sq. units.
