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Lapatulllka [165]
2 years ago
8

Write in vertex form. y = 8(x+)2 +

Mathematics
1 answer:
zepelin [54]2 years ago
7 0

Answer:

:The correct answer is :y = 8(x + 2)^2 + -15Step-by-step explanation:I just got the question correct.

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A random walker is observed to take a total of N steps, n of which are to the right (and the rest n^' are to the left). Suppose
ioda

Answer:

p = 0.635

Step-by-step explanation:

A step to the right is n and on ten different days, it was recorded to be

14, 13, 11, 12, 11, 12, 16, 16, 14, 8.

n = average of all the steps,

The average is the sum of variables divided by the number of variables

Average = (14+13+11+12+11+12+16+16+14+8)/10

Average = 12.7 steps.

σₙ² = variance of n

Variance is an average of the squared deviations from the mean.

[Σ(x - xbar)²/N]

Σ(x - xbar)² = (14-12.7)² + (13- 12.7² + (11-12.7)² + (12-12.7)² + (11-12.7)² + (12-12.7)² + (16-12.7)² + (16-12.7)² + (14-12.7)² + (8-12.7)² = 54.1

Variance = σₙ² = (54.1/10) = 5.41

standard deviation = σₙ = √(variance) = √5.41 = 2.326.

The proportion, p can be computed in two ways.

Mean = Np or standard deviation = √[Np(1-p)]

where N = total number of steps = 20

Mean = 12.7 = 20p

p = (12.7/20) = 0.635

Or

Standard deviation = 2.326 = √[20p(1-p)]

5.41 = 20p - 20p²

20p² - 20p + 5.41 = 0

Solving the quadratic equation,

p = 0.5 + 0.143i or p = 0.5 - 0.143i

not a unique or feasible solution, hence, the probability of a step to the right remains p = 0.635

Hope this Helps!!!

5 0
3 years ago
The equation y + 6 = one-third (X minus 9) is written in point-slope form. What is the equation written in slope-intercept form?
rosijanka [135]

Answer:

y = \frac{1}{3} x - 9

Step-by-step explanation:

The equation of a line in slope- intercept form is

y = mx + c

Given

y + 6 = \frac{1}{3} (x - 9) ← distribute

y + 6 = \frac{1}{3} x - 3 ( subtract 6 from both sides )

y = \frac{1}{3} x - 9 ← in slope- intercept form

3 0
3 years ago
Read 2 more answers
Express 140 as a product of its prime factors
gogolik [260]

Answer:

140=7×2×2×5

Step-by-step explanation:

4 0
3 years ago
Find the equation of a straight line passing throught the point listed and having the given gradient. Express your answer in the
Igoryamba
First let's try to find the equation in this form : <span>y = mx + c 

The gradient is given 3 . In a line's equation, x's coefficient represents the line's gradient.

So equation of a line with the gradient of 3, would look like this ;

</span>y= 3x + c
<span>
Now a point that the line passes through is given, (1, 2) 

This point's x-coordinate is 1 and y-coordinate is 2.

So we'll plug its x-coordinate value in the equation and also y-coordinate value. So we can solve it.

As you know, </span>x=1 and y=2

y = 3x + c

2\quad =\quad 3\cdot 1+c\\ \\ 2\quad =\quad 3+c\\ \\ 2-3\quad =\quad c\\ \\ -1\quad =\quad c

We found c = -1 

Also in a line's equation, c is constant and it represents the line's y-intercept

So let's build the line's equation.

m=3 and c=-1

y= mx + c

y= 3x -1

We found the line's equation in this form, y= mx + c

Now let's turn it into this form, ax + by + c = 0

y\quad =\quad 3x-1\\ \\ y-3x\quad =\quad -1\\ \\ y-3x+1\quad =\quad 0\\ \\ -3x+y+1\quad =\quad 0

Final answers,

\boxed { y\quad =\quad 3x-1 }

and 

\boxed { -3x+y+1\quad =\quad 0 }

I hope this was clear enough :)




<span>


</span>
5 0
3 years ago
Read 2 more answers
Find the slope of the line that is perpendicular to the joining line P (2,-3) and Q (-3,-2)
azamat

m =(y2-y1)/(x2-x1)

m =(-2 + 3 )/(-3 -2)

m = 1/-5

m = -1/5

slope of the line that is perpendicular  = 5


8 0
3 years ago
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