<span>Four friends were born on consecutive years.
The sum of their ages is 62. Let's find the age of the youngest friend:
</span><span>Formula:
4x + 6 = 62
=> First is to Subtract 6 from both sides
4x = 56
Then next thing to do is to divide 4 from both sides:
=> x = 14
14 + 14 + 1 + 14 + 2 + 14 + 3 = 62
62 = 62
Thus the youngest age is 14</span>
-4 since -4*-15=60
also gcd (60,15)=15
so 60/15=4/1
Answer:
12:30 a.m.
Step-by-step explanation:
You can automatically add 5 to the 7, 5 + 7 = 12. Then add 30 to the minuets. 00 + 30 = 30.
So, your answer is 12:30.
Hope this helps!!
We know that TV = TU + UV. Let's plug the values from the picture into our equation.
x + 25 = 9 + 2x + 28.
Let's combine like terms on the right side.
x + 25 = 2x + 37
Subtract 37 and x from both sides.
-12 = x
TV = x + 25 = -12 + 25 = 13
UV = 2x + 28 = 2(-12) + 28 = -24 + 28 = 4
6 divided by 4(3/5)
After multiplying the fraction we get 23/5
Dividing a fraction will result to multiplying
6 * 23/5
138/5 is the answer.
