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AleksandrR [38]
3 years ago
6

Katie and Jennifer are playing a game. • Katie and Jennifer each started with 100 points. • At the end of each turn, Katie’s poi

nts doubled. • At the end of each turn, Jennifer’s points increased by 200. At the start of which turn will Katie first have more points than Jennifer?
Mathematics
2 answers:
Mrrafil [7]3 years ago
4 0
The answer to this question is actually just simple arithmetic. At the end of the first round, Katie and Jenny will have 100 points each. In the second round, Katie and Jenny will have 200 points and 300 points respectively. At the third round, Katie and Jenny will both have 400 points. At the fourth round, Katie and Jenny will have 800 and 600 points respectively. So the turn at which Katie will have more points than Jenny is the fourth round since Katie has 800 and Jenny has 600. 
e-lub [12.9K]3 years ago
4 0
Wow thats my answer

hope he helped


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Answer:C.45

Step-by-step explanation:

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22.67

Step-by-step explanation:

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Find the x-coordinates of any relative extrema and inflection point(s) for the function f(x) = 6x(1/3) + 3x(4/3). You must justi
stealth61 [152]
Applying our power rule gets us our first derivative,

\rm f'(x)=6\frac13x^{-2/3}+3\cdot\frac43x^{1/3}

simplifying a little bit,

\rm f'(x)=2x^{-2/3}+4x^{1/3}

looking for critical points,

\rm 0=2x^{-2/3}+4x^{1/3}

We can apply more factoring.
I hope this next step isn't too confusing.
We want to factor out the smallest power of x from both terms,
and also the 2 from each.

0=2x^{-2/3}\left(1+2x\right)

When you divide x^(-2/3) out of x^(1/3),
it leaves you with x^(3/3) or simply x.

Then apply your Zero-Factor Property,

\rm 0=2x^{-2/3}\qquad\qquad\qquad 0=(1+2x)

and solve for x in each case to find your critical points.

Apply your First Derivative Test to further classify these points. You should end up finding that x=-1/2 is an relative extreme value, while x=0 is not.

Let's come back to this,

\rm f'(x)=2x^{-2/3}+4x^{1/3}

and take our second derivative.

\rm f''(x)=-\frac43x^{-5/3}+\frac43x^{-2/3}

Looking for inflection points,

\rm 0=-\frac43x^{-5/3}+\frac43x^{-2/3}

Again, pulling out the smaller power of x, and fractional part,

\rm 0=-\frac43x^{-5/3}\left(1-x\right)

And again, apply your Zero-Factor Property, setting each factor to zero and solving for x in each case. You should find that x=0 and x=1 are possible inflection points.

Applying your Second Derivative Test should verify that both points are in fact inflection points, locations where the function changes concavity.
8 0
3 years ago
Mixed numbers greater than 6 but less than 7 use an interval of 1/6 between each pair of numbers
GaryK [48]

Answer:

[6\frac{1}{6},6\frac{1}{3},6\frac{1}{2},6\frac{2}{3},6\frac{5}{6}]

Step-by-step explanation:

we have the compound inequality

6 < x < 7

where

x is a mixed number

so

The solution for the compound inequality are the numbers

[6\frac{1}{6},6\frac{2}{6},6\frac{3}{6},6\frac{4}{6},6\frac{5}{6}]

Simplify the numbers

[6\frac{1}{6},6\frac{1}{3},6\frac{1}{2},6\frac{2}{3},6\frac{5}{6}]

5 0
3 years ago
T
Marianna [84]

Solution:

<u>Note that:</u>

  • AB = EF
  • BC = EG = 6x - 8
  • 7x - 19 = 2x + 11
  • Perimeter of triangle: 24 + 2x + 11 + 6x - 8

<u>Solving for x:</u>

  • 7x - 19 = 2x + 11
  • => 7x - 2x = 19 + 11
  • => 5x = 30
  • => x = 30/5 = 6

<u>Substitute the value of x into the expression (24 + 2x + 11 + 6x - 8): </u>

  • 24 + 2x + 11 + 6x - 8
  • => 24 + 2(6) + 11 + 6(6) - 8
  • => 24 + 12 + 11 + 36 - 8
  • => 24 + 12 + 3 + 36
  • => 75 units

The perimeter of the triangle ABC is 75 units.

7 0
2 years ago
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