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Brut [27]
3 years ago
7

A study conducted in 2000 found that the mean number of children under 18 per household in a certain community was 1.7. A statis

tician is trying to determine whether this number has changed in the last 6 years. She declares the null and alternative hypotheses to be:
H0: The mean number of children per household in 2000 is 1.7
H1: The mean number of children per household in 2000 is not 1.7
Which of the following statements is true about this test?

a) this is a right tailed test
b) this is a left tailed test
c)this is a two tailed test d) this is a step tailed test
Mathematics
1 answer:
Margarita [4]3 years ago
3 0

Answer:

c). Two tailed test

Step-by-step explanation:

The given hypothesis are

Null hypothesis: H0:μ= 1.7

Alternative hypothesis: H1:μ≠ 1.7

The alternative hypothesis demonstrates that  mean number of children are not 1.7 in 2000. This means that mean number of children can be greater than 1.7 or mean number of children can be less than 1.7. Thus, the given alternative hypothesis indicates the two tailed test.

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A jar contains 99 large red​ marbles, 66 small red​ marbles, 88 large blue​ marbles, and 55 small blue marbles. if a marble is c
aliina [53]
I think it would be the first one
3 0
2 years ago
Use the distance formula to determine the distance between (-8,10) and (-6,7)
hjlf

Answer:

Distance: \sqrt{13} units

Step-by-step explanation:

The distance formula is d=\sqrt{(x_2-x_1)^2+(y_2-y_1)^2} where:

  • d is the distance between points (x_1,y_1) and (x_2,y_2)
  • (x_1,y_1) are the coordinates of the first point
  • (x_2,y_2) are the coordinates of the second point

We are given that:

  • (x_1,y_1)=(-8,10)
  • (x_2,y_2)=(-6,7)

To determine the value of our distance, d, we plug in our given information into the formula and solve for

d=\sqrt{(x_2-x_1)^2+(y_2-y_1)^2}

d=\sqrt{(-6-(-8))^2+(7-10)^2}

d=\sqrt{(-6+8)^2+(-3)^2}

d=\sqrt{(2)^2+(-3)^2}

d=\sqrt{4+9}

d=\sqrt{13}

Therefore, the distance between (-8,10) and (-6,7) is \sqrt{13} units.

See the attached graph for a visual.

5 0
2 years ago
What is the following quotient?
Sergio039 [100]

Answer:

\frac{\sqrt{3} }{4}

Step-by-step explanation:

\frac{1}{1+\sqrt{3} }

basically we want to get rid of the √3 on the denominator

to do so we multiply it by itself so it is a perfect square

but whatever we do to the top we must do to the bottom so we multiply the numerator and denominator by √3

\frac{1*\sqrt{3} }{1+\sqrt{3}*\sqrt{3}  }=\frac{\sqrt{3} }{1+\sqrt{9} } =\frac{\sqrt{3} }{1+3} =\frac{\sqrt{3} }{4}

notes : √3 × √3 = √9 which is a perfect square that simplfies to 3

3 0
1 year ago
Which expression is equivalent to 9 x squared minus 2 y + 3 x squared minus 3 y? 6 x squared minus y + 6 x squared minus 5 y 6 x
RoseWind [281]

Answer:

10 x squared minus 4 y + 2 x squared minus y

Step-by-step explanation:

9x^2-2y+3x^2-3y

Collect like terms

9x^2+3x^2-2y-3y

=12x^2-5y

10 x squared minus 4 y + 2 x squared minus y

10x^2-4y+2x^2-y

Collect like terms

10x^2+2x^2-4y-y

=12x^2-5y

9x^2-2y+3x^2-3y is equivalent to

10x^2-4y+2x^2-y

Check all the options

6 x squared minus y + 6 x squared minus 5 y

6x^2-y+6x2-5y

12x^2-6y

6 x squared minus y + 3 x squared minus 4 y

6x^2-y+3x^2-4y

9x^2-5y

10 x squared minus 4 y + 2 x squared minus y

10x^2-4y+2x^2-y

12x^2-5y

11 x squared + 2 y + x squared minus 3 y

11x^2+2y+x^2-3y

12x^2-y

5 0
2 years ago
Read 2 more answers
HELP NEEDED PLEASE!!!!
Vlad [161]

Answer:

B√134

Step-by-step explanation:

the answer is B(√134)

hope it helps

3 0
2 years ago
Read 2 more answers
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