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Mandarinka [93]
2 years ago
7

A child grew 3 1/4 inches one year and 4 3/4 inches the next year. How many inches did the child grow over the two years?

Mathematics
2 answers:
mixas84 [53]2 years ago
6 0

Answer:

The child grew 8 inches

Step-by-step explanation:

<u>Step 1:  Convert to improper fractions</u>

3\frac{1}{4}

\frac{1+(3*4)}{4}

\frac{1+12}{4}

\frac{13}{4}

4\frac{3}{4}

\frac{3+(4*4)}{4}

\frac{3+16}{4}

\frac{19}{4}

<u>Step 2:  Combine the fractions</u>

\frac{13}{4}+\frac{19}{4}

\frac{13+19}{4}

\frac{32}{4}

8

Answer:  The child grew 8 inches

svet-max [94.6K]2 years ago
3 0

Answer:

8 inches.

Step-by-step explanation:

3 1/4 + 4 3/4

= 3 + 4 + 1/4 + 3/4

= 7 + 4/4

= 7 + 1

= 8 inches.

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C=2*pi*r or c=pi*d
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Find the midpoint of the segment with the following endpoints (-3,-9)(-7,-3)
barxatty [35]

Answer:

(-5,-6)

Step-by-step explanation:

Let(-3,-9)=(x1,y1)

(-7,-3)=(x2,y2)

Using midpoint formula,

Midpoint(x,y)=((x1+x2)/2,(y1+y2)/2)

=((-3+(-7))/2,(-9+(-3))/2))

=((-3-7)/2),(-9-3)/2))

=((-10/2),(-12/2))

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8 0
4 years ago
A trapezoid was broken into two congruent triangles and a rectangle. A trapezoid is broken into 2 triangles and 1 rectangle. The
Naddika [18.5K]

complete question:

The picture below is the complete question.

Answer:

base of the triangles = 3 cm

Step-by-step explanation:

The trapezoid was broken into 2 congruent triangles and a rectangle. The 2 triangle have a height of 12 cm . The rectangle has a height of 12 cm and width of 14 cm .

The base length of the triangle can be computed as follows.

Note a congruent triangle have exactly the same three sides and exactly the same three angles.

area of a triangle = 1/2 × base × height

From the area of the trapezoid one can calculate the sides of the triangle.

area of the trapezoid = 1/2 × (a + b)h

where

a = top side

b = base side

h = height

area of the trapezoid = 1/2 × (a + b)h

area of the trapezoid = 1/2 × (14 + 20)12

area of the trapezoid = 1/2 × 34 × 12

area of the trapezoid = 34 × 6

area of the trapezoid = 204 cm²

204 = area of the triangles + area of the rectangle

204 =2 (1/2bh) + lw

where

b = base of triangle

h = height of triangle

l = length of rectangle

w = width of rectangle

204 = bh + (14 × 12)

204 = 12b + 168

12b = 204 - 168

12b = 36

divide both sides by 12

b = 36/12

b = 3 cm

base of the triangles = 3 cm

 

3 0
3 years ago
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