D. Decreases in Quadrant ||| , i’m pretty sure
1) true
2)false
Step-by-step explanation:
1) 5(3)+2(4) = 23
= 15+8=23
23=23
thus, (3,4) is solution for 5x + 2y = 23
2) 5(0)+2(4) =23
= 0+8 is not 23
thus, (0,4) is not solution for 5x + 2y = 23
Answer:
![yes \: he \: is \: correct \\ \underline{\boxed{(\triangle{ \delta}) = 8}}](https://tex.z-dn.net/?f=yes%20%5C%3A%20he%20%5C%3A%20is%20%5C%3A%20correct%20%5C%5C%20%20%20%5Cunderline%7B%5Cboxed%7B%28%5Ctriangle%7B%20%5Cdelta%7D%29%20%3D%208%7D%7D)
Step-by-step explanation:
![change \: in \: temp. \: ( \triangle{ \delta}) = t_2 - t_1 \\ hence \to \\( \triangle{ \delta}) = (- 2) - (- 10) \\ (\triangle{ \delta}) = - 2 + 10 \\ (\triangle{ \delta}) = 10 - 2 \\ (\triangle{ \delta}) = 8](https://tex.z-dn.net/?f=change%20%5C%3A%20in%20%5C%3A%20temp.%20%5C%3A%20%28%20%5Ctriangle%7B%20%5Cdelta%7D%29%20%3D%20t_2%20-%20t_1%20%5C%5C%20hence%20%5Cto%20%5C%5C%28%20%5Ctriangle%7B%20%5Cdelta%7D%29%20%3D%20%20%28-%202%29%20-%20%28-%2010%29%20%5C%5C%20%28%5Ctriangle%7B%20%5Cdelta%7D%29%20%3D%20%20-%202%20%2B%2010%20%5C%5C%20%28%5Ctriangle%7B%20%5Cdelta%7D%29%20%3D%2010%20-%202%20%5C%5C%20%28%5Ctriangle%7B%20%5Cdelta%7D%29%20%3D%208)
Answer:
![32x^{2} + 1 / 16x](https://tex.z-dn.net/?f=32x%5E%7B2%7D%20%20%2B%201%20%2F%2016x)
Step-by-step explanation:
x2+1/4x4
2x+(1/4*4x)
2x+(1/16x)
= 32x^2+1/16x
24= 2l+2w
l=2w
Substitute for l
24= 2(2w)+2w
24= 6w
4=w
Plug in the w value
l=2(4)
l=8
Final answer: Length= 8 m, Width= 4 m