PLEASE ANSWER + BRAINLIEST!!!!

Use the given parent function f(x)=|x| to graph g(x)=|x+2|-4. use the ray tool and select two points to graph each ray.

marin [14]

Shown in the attached figure

<h2>Explanation:</h2>

The absolute value function is a function that takes the shape of a V. The pattern of the absolute value function is:

$f(x)=\mid x \mid$

So we need to use this function in order to obtain:

$g(x)=\mid x+2 \mid -4$

Recall that to translate a function vertically, we use the following rule:

$g(x)=f(x)+k \\ \\ \bullet \ If \ k>0 \ the \ graph \ of \ f(x) \ is \ translated \ k \ units \ up \\ \\ \bullet \ If \ k$

And to translate a function horizontally, we use the following rule:

$g(x)=f(x+c) \\ \\ \bullet \ If \ c>0 \ the \ graph \ of \ f(x) \ is \ translated \ c \ units \ to \ the \ left \\ \\ \bullet \ If \ c$

Since:

$c=2>0 \ and \ k=-4$

Then:

<em>g(x) is the translation of f(x) 2 units to the left and 4 units down</em>

<em />

<h2>Learn more:</h2>

Transformations in real-world problems: brainly.com/question/1033817

#LearnWithBrainly

8 0

3 years ago

The solution for the following system of linear equation 3m-2n=13 is (2,-1) true or false

Tanya [424]

Answer:

Not True

Step-by-step explanation:

>_<

4 0

3 years ago

Read 2 more answers

Please help with this, thanks

Readme [11.4K]

Answer:

BDC is half of mBC = 11°

Easily you see that C is A + BDC = 23°

Since C = 23° so mDC is twice = 46°

x

8 0

3 years ago

A company manufactures and sells x television sets per month. The monthly cost and price-demand equations are C(x)equals72 com

solmaris [256]

Answer:

Part (A)

1. Maximum revenue: $450,000

Part (B)

2. Maximum protit: $192,500

3. Production level: 2,300 television sets

4. Price: $185 per television set

Part (C)

5. Number of sets: 2,260 television sets.

6. Maximum profit: $183,800

7. Price: $187 per television set.

Explanation:

<u>0. Write the monthly cost and price-demand equations correctly:</u>

Cost:

$C(x)=72,000+70x$

Price-demand:

$p(x)=300-\dfrac{x}{20}$

Domain:

$0\leq x\leq 6000$

<em>1. Part (A) Find the maximum revenue</em>

Revenue = price × quantity

Revenue = R(x)

$R(x)=\bigg(300-\dfrac{x}{20}\bigg)\cdot x$

Simplify

$R(x)=300x-\dfrac{x^2}{20}$

A local maximum (or minimum) is reached when the first derivative, R'(x), equals 0.

$R'(x)=300-\dfrac{x}{10}$

Solve for R'(x)=0

$300-\dfrac{x}{10}=0$

$3000-x=0\\\\x=3000$

Is this a maximum or a minimum? Since the coefficient of the quadratic term of R(x) is negative, it is a parabola that opens downward, meaning that its vertex is a maximum.

Hence, the maximum revenue is obtained when the production level is 3,000 units.

And it is calculated by subsituting x = 3,000 in the equation for R(x):

R(3,000) = 300(3,000) - (3000)² / 20 = $450,000

Hence, the maximum revenue is $450,000

<em>2. Part (B) Find the maximum profit, the production level that will realize the maximum profit, and the price the company should charge for each television set. </em>

i) Profit(x) = Revenue(x) - Cost(x)

Profit (x) = R(x) - C(x)

$Profit(x)=300x-\dfrac{x^2}{20}-\big(72,000+70x\big)$

$Profit(x)=230x-\dfrac{x^2}{20}-72,000\\\\\\Profit(x)=-\dfrac{x^2}{20}+230x-72,000$

ii) Find the first derivative and equal to 0 (it will be a maximum because the quadratic function is a parabola that opens downward)

Profit' (x) = -x/10 + 230

-x/10 + 230 = 0

-x + 2,300 = 0

x = 2,300

Thus, the production level that will realize the maximum profit is 2,300 units.

iii) Find the maximum profit.

You must substitute x = 2,300 into the equation for the profit:

Profit(2,300) = - (2,300)²/20 + 230(2,300) - 72,000 = 192,500

Hence, the maximum profit is $192,500

iv) Find the price the company should charge for each television set:

Use the price-demand equation:

p(x) = 300 - x/20

p(2,300) = 300 - 2,300 / 20

p(2,300) = 185

Therefore, the company should charge a price os $185 for every television set.

<em>3. Part (C) If the government decides to tax the company $4 for each set it produces, how many sets should the company manufacture each month to maximize its profit? What is the maximum profit? What should the company charge for each set?</em>

i) Now you must subtract the $4 tax for each television set, this is 4x from the profit equation.

The new profit equation will be:

Profit(x) = -x² / 20 + 230x - 4x - 72,000

Profit(x) = -x² / 20 + 226x - 72,000

ii) Find the first derivative and make it equal to 0:

Profit'(x) = -x/10 + 226 = 0

-x/10 + 226 = 0

-x + 2,260 = 0

x = 2,260

Then, the new maximum profit is reached when the production level is 2,260 units.

iii) Find the maximum profit by substituting x = 2,260 into the profit equation:

Profit (2,260) = -(2,260)² / 20 + 226(2,260) - 72,000

Profit (2,260) = 183,800

Hence, the maximum profit, if the government decides to tax the company $4 for each set it produces would be $183,800

iv) Find the price the company should charge for each set.

Substitute the number of units, 2,260, into the equation for the price:

p(2,260) = 300 - 2,260/20

p(2,260) = 187.

That is, the company should charge $187 per television set.

7 0

3 years ago

Find the x-intercept of the function f(x) = a^x + 1 - 1.

babymother [125]

I am not certain of what you wrote for the function but will assume that is likely exponential function or quadratic function.

First, (quadratic function) To solve this, you must know the quadratic formula. The x-intercept is value(s) that has the output value(y) of 0.

If the vertex of the quadratic function of (0,0), there is only one x-intercept. The number and value of the x-intercept depends on the slope and vertical displacement.

Second, (exponential function) note that there is no x-intercept. For instance, if a is 2, is there such value y that 2^y is 0? The smallest exponential value that is an integer is 1. Even broadening the limit to rational numbers, no such exponential value can have the result of 0. Therefore, in the basic form of exponential function, there is no x-intercept.

4 0

3 years ago