Answer:
P_max = 9.032 KN
Step-by-step explanation:
Given:
- Bar width and each side of bracket w = 70 mm
- Bar thickness and each side of bracket t = 20 mm
- Pin diameter d = 10 mm
- Average allowable bearing stress of (Bar and Bracket) T = 120 MPa
- Average allowable shear stress of pin S = 115 MPa
Find:
The maximum force P that the structure can support.
Solution:
- Bearing Stress in bar:
T = P / A
P = T*A
P = (120) * (0.07*0.02)
P = 168 KN
- Shear stress in pin:
S = P / A
P = S*A
P = (115)*pi*(0.01)^2 / 4
P = 9.032 KN
- Bearing Stress in each bracket:
T = P / 2*A
P = T*A*2
P = 2*(120) * (0.07*0.02)
P = 336 KN
- The maximum force P that this structure can support:
P_max = min (168 , 9.032 , 336)
P_max = 9.032 KN
Your answer is three hundred and thirty six (336)
Answer:
1 -5
don't know the answer of q2 and q3
1) The equation of the parallel line in Slope Intercept Form is; y = -x - 1
2) The equation of the perpendicular line in Slope Intercept Form is;
y = ³/₂x - 4
<h3>How to write equation in Slope Intercept Form?</h3>
1) When two lines are parallel, it means their slopes are the same.
Formula for equation in slope intercept form is;
y = mx + c
where;
m is slope
c is y-intercept
Thus, slope of y = -x + 1 is m = -1.
Equation of parallel line is;
(y - (-5))/(x - 4) = -1
y + 5 = -x + 4
y = -x - 1
2) When two lines are perpendicular, it means their slopes are the negative inverse of each other. Thus;
Slope of line = -2/3 and so slope of perpendicular line = 3/2. Thus, equation of new line is;
(y + 1)/(x - 2) = 3/2
2y + 2 = 3x - 6
2y = 3x - 8
y = ³/₂x - 4
Read more about slope intercept form at; brainly.com/question/1884491
#SPJ1
It would be: 1- 5/8 = 3/8
3/8 * 10 = 30/8 = 3.75 inches
