Graph the lines by making a table. a. y = 2x = 4
1 answer:
Answer:
Given y-2x=4 →y=2x+4
Table of Solutions
xy = 2x + 4(x, y) * P * o * i * n * t
0 y = 2(0) + 4 = 4 (0,4)A(0,4)
2 y = 2(-2) + 4 = 0 (-2, 0) B(-2, 0)
1y = 2(1) + 4 = 6(1, 6) C(1, 6)
Plotting the points A, B and C on the graph paper and joint them to get the straight line BC as shown in graph sheet. This line is the required graph of the equation y - 2x = 4 .
(i) Plot the point (2, 8) on the graph paper. From the graph it is clear that the point (2, 8) lies on the line.
Checking algebraically: On substituting (2, 8) in the
given equation, we get LHS y-2x=8-2×2=8-4-4 RHS, So (2, 8) is a solution
(ii) Plot the point (4, 2) on the graph paper. You fin that (4, 2) does not lie on the line.
Checking algebraically: By substituting (4, 2) in the given equation we have
LHS =y-2x=2-2×4-2-8--6
=RHS, So (4, 2) is not a solution.
Step-by-step explanation:
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Answer:
The probability that an athlete chosen is either a football player or a basketball player is 56%.
Step-by-step explanation:
Let the athletes which are Football player be 'A'
Let the athletes which are Basket ball player be 'B'
Given:
Football players (A) = 13%
Basketball players (B) = 52%
Both football and basket ball players = 9%
We need to find probability that an athlete chosen is either a football player or a basketball player.
Solution:
The probability that athlete is a football player =
The probability that athlete is a basketball player =
The probability that athlete is both basket ball player and football player =
We have to find the probability that an athlete chosen is either a football player or a basketball player .
Now we know that;
Hence The probability that an athlete chosen is either a football player or a basketball player is 56%.