2 years ago

The vertex of -5(x+2)^2-6

Mathematics

1 answer:

4vir4ik [10]2 years ago

7 0

Answer:

(0,6).

Step-by-step explanation:

Consider the standardised form of y=ax2+bx+c. Written as y=a(x2+bax)+c. xvertex=(−12)×ba → (−12)×0−1=0.

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If a pond has a major axis of 68 feet and a minor axis of 32 feet how far apart are the foci

Bogdan [553]

Answer:

The distance between foci is 60 feet

Step-by-step explanation:

we are given

a pond has a major axis of 68 feet

so, $a=\frac{68}{2} =34$

a minor axis of 32 feet

so, $b=\frac{32}{2} =16$

now, we know ellipse formula

$c^2=a^2-b^2$

where

c is the distance between center and focus

so, we can plug it and find c

$c^2=34^2-16^2$

$c=30$

Distance between foci is

$=2c$

$=2\times 30$

$=60$

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Ulleksa [173]

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wel

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matrenka [14]

Answer:

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Please help with these questions!

Colt1911 [192]

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