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dusya [7]
3 years ago
9

You need to put your reindeer, Rudy, Ezekiel, Gloopin, Bloopin, and Prancer, in a single-file line to pull your sleigh. However,

Bloopin and Rudy are fighting, so you have to keep them apart, or they won't fly. How many ways can you arrange your reindeer?
Mathematics
1 answer:
topjm [15]3 years ago
6 0
If the reindeer do not fight, there are 5!=120 ways to line them up in a straight line.
Out of these, Bloopin and Rudy are together in 4!=24 times.  Similarly Rudy and Bloopin will be together 4!=24 times.  So the number of ways they are not together is 120-24-24=72 ways.
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Help help help።help plz​
In-s [12.5K]

Answer:

The perimeter is 240

Step-by-step explanation:

The side length is 60 and 60*4=240

hope this help!

7 0
2 years ago
Consider H0: μ = 45 versus H1: μ < 45. A random sample of 25 observations produced a sample mean of 41.8. Using α = .025 and
a_sh-v [17]
Given
H0: \ \mu=45 \\  \\ H1: \ \mu\ \textless \ 45
This is a one-tailed test.

z= \frac{41.8-45}{6/ \sqrt{25} } = \frac{-3.2}{6/5} = \frac{-3.2}{1.2} =-2.6667

P(z\ \textless \ -2.6667)=0.00383

Since the p-value of the sample statistic (0.00383) is less that the significant level (0.025), we reject the null hypothesis.
5 0
3 years ago
Slope pls help ASAP due tonight
kow [346]

Answer:

y=x+ -5

i think

4 0
2 years ago
Read 2 more answers
Thompson and Thompson is a steel bolts manufacturing company. Their current steel bolts have a mean diameter of 141 millimeters,
tiny-mole [99]

Answer:

Probability that the sample mean would be greater than 141.4 millimetres is 0.3594.

Step-by-step explanation:

We are given that Thompson and Thompson is a steel bolts manufacturing company. Their current steel bolts have a mean diameter of 141 millimetres, and a standard deviation of 7.

A random sample of 39 steel bolts is selected.

Let \bar X = <u><em>sample mean diameter</em></u>

The z score probability distribution for sample mean is given by;

                            Z  =  \frac{ \bar X-\mu}{\frac{\sigma}{\sqrt{n} }  } }  ~ N(0,1)

where, \mu = population mean diameter = 141 millimetres

           \sigma = standard deviation = 7 millimetres

           n = sample of steel bolts = 39

Now, Percentage the sample mean would be greater than 141.4 millimetres is given by = P(\bar X > 141.4 millimetres)

      P(\bar X > 141.4) = P( \frac{ \bar X-\mu}{\frac{\sigma}{\sqrt{n} }  } } > \frac{141.4-141}{\frac{7}{\sqrt{39} }  } } ) = P(Z > 0.36) = 1 - P(Z \leq 0.36)

                                                            = 1 - 0.6406 = <u>0.3594</u>

The above probability is calculated by looking at the value of x = 0.36 in the z table which has an area of 0.6406.

8 0
3 years ago
Sal's Sandwich Shop sells wraps and sandwiches as part of its lunch specials. The profit on every sandwich is $2 and the profit
blondinia [14]

Answer:

Step-by-step explanation: For part 1, it makes sense that the form is y = m + c. So, it is a simply rearrangement of the equation to start with, in order to make  the subject. This is the graph in slope-intercept form. From here it is easy to see that gradient  = and the y-intercept = 490. The easiest way to draw a straight-line graph, such as this one, is to plot the y-intercept, in this case (0, 490), then plot another point either side of it at a fair distance (for example substitute  = -5 and  = 5 to procure two more sets of co-ordinates). These can be joined up with a straight line to form a section of the graph, which would otherwise extend infinitely either side - use the specified range in the question for x-values, and do not exceed it (clearly here the limit of -values is 0 ≤ x ≤ 735, since neither x nor y can be negative within the context of the question - the upper limit was found by substituting  = 0). In easy terms, the graph of this function represents how the value of the function varies as the value of x varies. Looking back at the question context, this graph specifically represents how many wraps could have been sold at each number of sandwich sales, in order to maintain the same profit of $1470. When the profit is higher, the gradient is not changed (this is defined by the relationship between the $2 and $3 prices, not the overall profit) - instead the -intercept is higher, therefore we have gleaned that the new y-intercept is 531. Clearly I cannot see the third straight line. However the method for finding the equation of a straight line graph is fairly simple:

1. Select two points on the line and write down their coordinates

2. The gradient of the line =

3. Find the change in  (Δ

4. Find the change in  (Δ

5. Divide the result of stage 3 by the result of stage 4

6. This is your gradient

7. Take one of your sets of coordinates, and arrange them in the form , where your  is the gradient you just calculated

8. There is only one variable left, which is  (the y-intercept). Simply solve for this

9. Now generalise the equation, in the form , by inputting your gradient and y-intercept whilst leaving the coordinates as  and

For example if the two points were (1, 9) and (4, 6):

Δ = 6 - 9 = -3

Δ = 4 - 1 = 3

=  = -1

I choose the point (4, 6)

6 = (-1 * 4) + c

6 = c - 4

c = 10

Therefore, generally,

Within the context of the question, I imagine the prices of the two lunch specials will be the same in the third month and hence the gradient will still be  - this means steps 1-6 can be omitted. Furthermore if the axes are clearly labelled, you may even be able to just read off the y-intercept and hence dispose with steps 1-8!

4 0
3 years ago
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