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3 years ago

A square with side length 5.5 mm is increased by a factor of 11. What will be the perimeter of the square after dilation?

Mathematics

1 answer:

lions [1.4K]3 years ago

3 0

Answer:

The perimeter of the square after dilation will be 242 mm

Step-by-step explanation:

$5.5*11 = 66.5\\P = 4s\\P = 4(66.5mm)\\P = 242mm$

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Elis [28]

Answer:

Alternate

Step-by-step explanation:

Because, as you can see, it is alternating

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3 years ago

Can someone solve this

77julia77 [94]

Answer:

A ≈ 269.81 cm²

Step-by-step explanation:

This shape is a hexagon (it has 6 sides) so let's use the formula for the area of a hexagon.

A = $\frac{3\sqrt{3} }{2} s^{2}$

Where s is the length of the sides

Substitute:

A = $\frac{3\sqrt{3} }{2} s^{2}$

A = $\frac{3\sqrt{3} }{2} 10^{2}$

Solve:

A = $\frac{3\sqrt{3} }{2} 10^{2}$

A = $\frac{3\sqrt{3} }{2} 100$

Multiply the numerator:

A = $\frac{3\sqrt{3} }{2} 100$

A ≈ $\frac{5.12 }{2} 100$

(The numerator reflects a rounded number, but the actual calculations are exact)

Divide the fraction:

A ≈ $\frac{5.12 }{2} 100$

A ≈ 2.6(100)

Multiply:

A ≈ 2.6(100)

A ≈ 269.81 cm²

Therefore, the area is approximately 269.82 cubic centimeters.

6 0

3 years ago

How long will it take an emperor penguin to swim 14 miles if it is swimming 7 mph

xz_007 [3.2K]

It will take the penguin 2 hours i think
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3 years ago

a rectangle has a length of (x +6) feet and width of (x-2) feet. has a area of 48 feet squared, find the dimensions

Shalnov [3]

(x^2)+4x-12=48

I Hope this is what you were looking for. If it isn't this just plug it in

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3 years ago

According to the latest survey the mean world lifespan is 68.8 years the university of Oregon wants to see if the average life s

pishuonlain [190]

Answer:

Step-by-step explanation:

We would set up the hypothesis test.

For the null hypothesis,

µ = 68.8

For the alternative hypothesis,

µ ≠ 68.8

This is a two tailed test.

Since the number of samples is small and no population standard deviation is given, the distribution is a student's t.

Since n = 26,

Degrees of freedom, df = n - 1 = 26 - 1 = 25

t = (x - µ)/(s/√n)

Where

x = sample mean = 72.8

µ = population mean = 68.8

s = samples standard deviation = 2.5

t = (72.8 - 68.8)/(2.5/√26) = 8.16

We would determine the p value using the t test calculator. It becomes

p < 0.00001

Assuming a significance level of 0.05, then

Since alpha, 0.05 > than the p value, then we would reject the null hypothesis. Therefore, At a 5% level of significance, the sample data showed significant evidence that the average life span of the residence of Oregon differs from the world average.

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3 years ago