Answer:
x-intercept= (3⅓, 0)
y-intercept= (0, 4²⁄₇)
Please see the attached picture for the graph.
Step-by-step explanation:
-9x -7y= -30
Let's simplify the equation by dividing both sides by -1.
9x +7y= 30
x- intercept occurs at y= 0.
When y= 0,
9x +7(0)= 30
9x= 30
x= 30 ÷9
Thus, x- intercept occurs at (3⅓, 0).
y-intercept occurs at x= 0.
When x= 0,
9(0) +7y= 30
7y= 30
y= 30 ÷7
Thus, y- intercept occurs at (0, 4²⁄₇).
_____
To graph the equation, draw the x and y axis on a graph paper. Use an appropriate scale to divide the line into equal parts. Next, plot the points (3⅓, 0) and (0, 4²⁄₇). Then, join the two points with a straight line.
Notes:
- x- intercept is the point at which the graph cuts through the x- axis. In this case, your x- axis is the horizontal line that runs from left to right of your graph paper. In order for a point to be on this horizontal line, look at the y- axis and notice that it sits at y= 0. The same reason applies for why the y- intercept occurs at x= 0. This has to do with the two axis cutting each other at the point (0,0), resulting in the x and y coordinates of 0 for the y and x intercepts respectively.
- Simplifying the equation in the first step is not necessary, but it is a good practice and might reduce carelessness.
75= 5^2h/3
75= 25h/3
225= 25h
9=h
Final answer: 9ft
Answer:
x = 40
Step-by-step explanation:
In order for m and n to be parallel, the corresponding angles need to be equal. Therefore we get the equation:
3x = 120
Divide both sides by 3 to get:
x = 40
Answer:
2 solutions
Step-by-step explanation:
Since the equations are not equal, they provide two solutions. Negative numbers provide no solutions. If they are equal to zero, they have one solution.
Answer:
a) we know that this is convergent.
b) we know that this might not converge.
Step-by-step explanation:
Given the is convergent
Therefore,
(a) The power series has radius of convergence at least as big as 8. So we definitely know it converges for all x satisfying -8<x≤8. In particular for x = -3
∴ is convergent.
(b) -8 could be right on the edge of the interval of convergence, and so might not converge