If JM=30 and LM=8, what is KM?

The rectangular area measures 30 ft by 25ft. The fencing that will be used comes in 25 ft sections. How many sections will you n

lbvjy [14]

Answer:

5

Step-by-step explanation:

8 0

3 years ago

What is the area of the trapezoid if a = 10 b= 18 and h = 6 inches?

yanalaym [24]

[ Answer ]

$\boxed{\bold{84 \ In.^{2} }}$

[ Explanation ]

Formula For Area Of Trapezoid: $\boxed{\bold{\frac{a \ + \ b}{2}Height }}$

-----------------------------------------

A = 10

B = 18

H = 6

Plug Numbers Into Equation: $\boxed{\bold{\frac{10 \ + \ 18}{2}Height }}$

Solve

10 + 18 = 28

28 ÷ 2 = 14

14 · 6 = 84

Final Answer

84

$\boxed{\bold{[] \ Eclipsed \ []}}$

4 0

3 years ago

After a college football team once again lost a game to their archrival, the alumni association conducted a survey to see if alu

valentina_108 [34]

Answer:

P-value for this hypothesis test is 0.00175.

Step-by-step explanation:

We are given that the alumni association conducted a survey to see if alumni were in favor of firing the coach.

A simple random sample of 100 alumni from the population of all living alumni was taken. Sixty-four of the alumni in the sample were in favor of firing the coach.

Let p = proportion of all living alumni who favored firing the coach

SO, Null Hypothesis, $H_0$ : p = 0.50 {means that the majority of alumni are not in favor of firing the coach}

Alternate Hypothesis, $H_A$ : p > 0.50 {means that the majority of alumni are in favor of firing the coach}

The test statistics that will be used here is One-sample z proportion statistics;

T.S. = $\frac{\hat p-p}{{\sqrt{\frac{\hat p(1-\hat p)}{n} } } } }$ ~ N(0,1)

where, $\hat p$ = sample proportion of the alumni in the sample who were in favor of firing the coach = $\frac{64}{100}$ = 0.64

n = sample of alumni = 100

So, test statistics = $\frac{0.64-0.50}{{\sqrt{\frac{0.64(1-0.64)}{100} } } } }$

= 2.92

Now, P-value of the hypothesis test is given by ;

P-value = P(Z > 2.92) = 1 - P(Z $\leq$ 2.92)

= 1 - 0.99825 = 0.00175

Therefore, the P-value for this hypothesis test is 0.00175.

4 0

3 years ago

At the beginning of year 1, Sam invests $700 at an annual compound interest

Aleksandr-060686 [28]

at the beginning of year 4, only 3 years have elapsed, the 4th year hasn't started yet, since it's at the beginning, so at the beginning of year 4 we can say only 4-1 years have elapsed.

$~~~~~~ \textit{Compound Interest Earned Amount} \\\\ A=P\left(1+\frac{r}{n}\right)^{nt} \quad \begin{cases} A=\textit{accumulated amount}\\ P=\textit{original amount deposited}\dotfill &\$700\\ r=rate\to 5\%\to \frac{5}{100}\dotfill &0.05\\ n= \begin{array}{llll} \textit{times it compounds per year}\\ \textit{annually, thus once} \end{array}\dotfill &1\\ t=\textit{elapsed years}\dotfill &3 \end{cases}$

$A=700\left( 1 + \frac{0.05}{1} \right)^{1\cdot 3}\implies A = 700(1+0.05)^3\implies A(4)=700(1+0.05)^{4-1} \\\\[-0.35em] ~\dotfill\\\\ ~\hfill A(n)=700(1+0.05)^{n-1}~\hfill$

6 0

2 years ago

If f=(2,3),(5,7),(5,4),(9,1), what is the range

lbvjy [14]

Answer: $Range:$ { $1,3,4,7$ }

Step-by-step explanation:

We know that, by definition, the Domain is the set of all the x-coordinates of the ordered pairs and the Range is the set of all the y-coordinates of the ordered pairs.

Therefore, given $f=(2,3),(5,7),(5,4),(9,1)$ , you can observe that the set of all second elements of ordered pairs (the values of "y") is the following:

{ $3,7,4,1$ }

Therefore, we can conclude that if $f=(2,3),(5,7),(5,4),(9,1)$ , then the range is:

$Range:$ { $1,3,4,7$ }

3 0

3 years ago

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