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guapka [62]
2 years ago
12

If JM=30 and LM=8, what is KM?

Mathematics
1 answer:
Varvara68 [4.7K]2 years ago
8 0

Answer:

Step-by-step explanation:

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Tyrone solved an algebraic equation correctly. He got the answer 5 = 3. This answer indicates that the solution to the equation
worty [1.4K]

Answer:

No solution.

Step-by-step explanation:

5 can't equal 3 my friend.

7 0
3 years ago
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Let f be a functions of degree 4 whose coefficients are real numbers: two of its zeros are - 3 and 4 - i. Explain why one of the
kvasek [131]

Answer:

Step-by-step explanation:

We have the following theorem, if f is a polynomial with real coefficients, we can factor it completely in factors of the degree at most 2.

Consider first a polynomial of degree two, hence it is a polynomial of the form ax^2+bx+c. The cuadratic formula tells us that the solutions are of the form

x = \frac{-b\pm \sqrt[]{b^2-4ac}}{2a}.

Note that square root, over the reals, tells us that the are only real solutions if b^2-4ac \geq 0. If that is not the case, say it's negative, the solution are complex. Then, the solutions are of the form

x = \frac{-b \pm i \sqrt[]{4ac-b^2}}{2a}. NOte that this means that if we have a complex number of the form a+bi that is a solution, then the number a-bi (who is called the complex conjugate) is also a solution.

Recall that when we have a polynomial f(x) whose a zero is the number c, then we can factor f as follows f(x) = (x-c) * p(x) where p(x) is another polynomial of lesser degree .

So far, we know that -3 and 4-i are zeros of the function f. Note that we are missing two zeros. But, since complex numbers are zeros of polynomial only by pairs (that is the number and its conjugate are zeros), then, we must have that one of the missing 2 zeros is a real number. We have 4-i as a zero, then, its complex conjugate must be also a zero, i.e 4+i is a zero.

8 0
3 years ago
Find the explicit formula for the sequence: 2,5,8,11,14
gizmo_the_mogwai [7]

Step-by-step explanation:

Given sequence is: 2,5,8,11,14

Here first term a = 2

Common Difference d = 3

\because \:  t_n = a +(n-1) d \\  \\  \therefore \: t_n = 2+(n-1) 3 \\  \\ \therefore \: t_n = 2+3n- 3 \\  \\  \huge \purple{ \boxed{\therefore \: t_n = 3n- 1}} \\  is \: the \: required \: explicit \: formula\\

4 0
2 years ago
borrow $5 from her father to buy items at a gas station Rose also borrowed $11 more from her brother Rose pays back $3.50 to her
Maru [420]
You would use the # line to add and subtract from Rose's total. The remaining amount that Rose still owes is $3. 

4 0
3 years ago
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If y varies directly as x, and y is 48 when x is 6, which expression can be used to find the value of y when x is 2?
sertanlavr [38]

y = ( 48 *2 ) / 6

Step-by-step explanation:

If y varies directly as x they are directly proportional, which means they relate to each other in the same way....

2 : y = 6: 48

what is y if x = 2?

The value of y can be found if you write it a two fracrions

2 : y = 6 : 48

2 / y = 6 / 48

cross multiply the fractions gives

6*y = 48 *2

divide left and right of the = sign by 6 gives the answer:

y = ( 48 *2 ) / 6

(if you solve it you get y = 12 but that was not the question).

Other method:

multiply left and right of the = sign by y

2 * y/y = y *6 / 48

6y / 48 = 2 * 1

multiply left and right of the = sign by 48

6y * 48/48 = ( 48 *2 )

6y = ( 48 *2 )

divide left and right of the = sign by 6

6/6* y = ( 48 *2 )/6

y = ( 48 *2 ) / 6

(if you solve it you get y = 12 but that was not the question).

4 0
3 years ago
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