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3 years ago

BRIANLIST ANSWER pls help i meant to put science

Mathematics

1 answer:

melisa1 [442]3 years ago

4 0

Answer:

I'd say Yev's description is best because it's the most specific to what it actually is in terms of science, while everyone else's descriptions are more like examples of different types and stages of energy, and where it could be found.

Hope this makes sense to ya :)

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W=1/9(x+y-z)<br> what’s the answer please help

KatRina [158]

Answer:

1/9x+1/9y-1/9z

Step-by-step explanation:

3 0

3 years ago

Gianna skied three times farther than Xavier. Xavier skied 4 miles. How far did Gianna ski

lina2011 [118]

Gianna=3x
Xavier=x
since x=4, than multiply 4 by 3 and you get 12 miles.
Gianna skied 12 miles.

Hope this helped!! :D

3 0

3 years ago

If the diagonals of a quadrilateral divide each other proportionally then it is a

Artist 52 [7]

Answer:

Step-by-step explanation:

trapezium

<h2>If the diagonals of a quadrilateral divide each other proportionally, then prove that the quadrilateral is a trapezium.</h2>

3 0

2 years ago

Straight forward questions I just don't know how to do them.

OLga [1]

Answer:

_____________________________

3 0

2 years ago

MATH HELP!!! 100PTS!!!

Lostsunrise [7]

Answer:

$x =\dfrac{20 +\sqrt{454}}{18}, \quad \dfrac{20 -\sqrt{454}}{18}$

Step-by-step explanation:

<u>Given functions</u>:

$p(x)=2x-4$

$r(x)=\dfrac{6x-1}{9x+1}$

Solve for p(x) = r(x):

$\begin{aligned}p(x) & = r(x)\\\implies 2x-4 & = \dfrac{6x-1}{9x+1}\\(2x-4)(9x+1)&=6x-1\\18x^2+2x-36x-4&=6x-1\\18x^2-40x-3&=0\end{aligned}$

As the found quadratic equation cannot be factored, use the Quadratic Formula to solve for x:

<u>Quadratic Formula</u>

$x=\dfrac{-b \pm \sqrt{b^2-4ac} }{2a}\quad\textsf{when }\:ax^2+bx+c=0$

Therefore:

$a=18, \quad b=-40, \quad c=-3$

Substitute the values of a, b and c into the <u>quadratic formula</u> and solve for x:

$\begin{aligned}\implies x & =\dfrac{-(-40) \pm \sqrt{(-40)^2-4(18)(-3)} }{2(18)}\\\\& =\dfrac{40 \pm \sqrt{1816}}{36}\\\\& =\dfrac{40 \pm \sqrt{4 \cdot 454}}{36}\\\\& =\dfrac{40 \pm \sqrt{4}\sqrt{454}}{36}\\\\& =\dfrac{40 \pm2\sqrt{454}}{36}\\\\& =\dfrac{20 \pm\sqrt{454}}{18}\end{aligned}$

Therefore, the solutions are:

$x =\dfrac{20 +\sqrt{454}}{18}, \quad \dfrac{20 -\sqrt{454}}{18}$

Learn more about quadratic equations here:

brainly.com/question/27750885

brainly.com/question/27739892

6 0

1 year ago