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olga55 [171]
3 years ago
13

Relationship between s and b helpppppp pleaseeee anyoneeeee

Mathematics
1 answer:
Harrizon [31]3 years ago
8 0

Answer:

see the table below

Step-by-step explanation:

s b

1 18

3 23

5 27

7 31

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A sample contains 300 grams of carbon-11, which has a half-life of 20 minutes.
vladimir2022 [97]

Answer:

Step-by-step explanation:

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2 years ago
What are interior angles
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Interior angles are the angles on the interior of a shape, for example the interior angles of a square are 90(degrees)

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4 years ago
What is the value of x? x+45=11 Enter your answer in the box in simplest form.
Ksivusya [100]

Isolate the x. Note the equal sign. What you do to one side, you do to the other. Subtract 45 from both sides

x + 45 (-45) = 11 (-45)

x = 11 - 45

x = -34

-34 is your answer

hope this helps


8 0
3 years ago
Read 2 more answers
I need help and the step to find
LUCKY_DIMON [66]

Answer: The answer is 169.

Step-by-step explanation:

Hope this helps! Have a good day! :)

4 0
3 years ago
Given the force field F, find the work required to move an object on the given oriented curve.
Aloiza [94]

Answer:

67/4

Step-by-step explanation:

Let C, D be the line segments that join (-1,0) with (0,8) and (0,8) with (2,8) respectively.

The work required by the force field F(x,y)=(x,y) is the curve integral

\large \int_{C+D}^{} F=\int_{C}^{}F+\int_{D}^{}F

the line segments that joins (-1,0) with (0,8) can be parameterized as

<em>r(t) = t(0,8)+(1-t)(-1,0)=(t-1,8t) with 0≤ t≤ 1 </em>

So

\large \int_{C}^{}F=\int_{0}^{1}F(r(t))\bullet r'(t)dt=\int_{0}^{1}(t-1,8t)\bullet (1,8)dt=\int_{0}^{1}(t-1+64t)dt=\\\\=\int_{0}^{1}(65t-1)dt=65\int_{0}^{1}tdt-\int_{0}^{1}dt=\frac{65}{2}-1=\frac{63}{2}

the line segments that joins (0,8) with (2,8) can be parameterized as

<em>r(t) = t(2,8)+(1-t)(0,8)=(2t,8) with 0≤ t≤ 1 </em>

hence

\large \int_{D}^{}F=\int_{0}^{1}F(r(t))\bullet r'(t)dt=\int_{0}^{1}(2t,8)\bullet (2,0)dt=\int_{0}^{1}4tdt=4\int_{0}^{1}tdt=2

and we have the work required by F to move a particle alon the path is

\large \int_{C}^{}F+\int_{D}^{}F=\frac{63}{2}+2=\frac{67}{4}

6 0
3 years ago
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