Point-slope form of a line: We need a point (x₀,y₀) and the slope "m";
y-y₀=m(x-x₀)
We have the next equation of line:
y=1/2 x-2 (slope-intercept form y=mx+b)
the slope of this line is 1/2 (m=1/2)
And any one point could be:
if x=0; then y=1/2 (0)-2=-2 (0,-2)
Therefore, we already have the point (0-,2) and the slope (m=1/2)
y-y₀=m(x-x₀)
y+2=1/2(x-0)
Answer: the point slope form of y=1/2 x-2; would be:
y+2=1/2(x-0)
Answer: y= 16 - 3/2x
Step-by-step explanation:
3x+2y=32 (subtract 3x from both sides)
2y=32-3x (divide both sides by 2)
y= 16 - 3/2 x
If solving for x:
3x + 2y = 32
3x = 32- 2y
x = 32/3 - 2/3 y
The answer is because the LCD of 4 and 10 is 20.
<span>1) force to pull it up 0.8 m
= 101.93 * 0.8
= 81.54 N
2) force for horizontal displacement
which can be found out by subtracting above value from total force applied
= 200-101.93
=98.07
Now finding horizontal displacement
98.07 = 101.93 * d
d= 0.96 m
Now since we found out hori. and vertical dist. apply Pythagoras theorem to find out length of ramp.
l^2= 0.96 ^2 + 0.8 ^2
= 0.9216 + 0.64
= 1.56
L = 1.25 m approx.</span>
.. Please... Please tell me you know fractions at least well enough to know this ;_;
3/4 is like 0.75, yeh?
3/8 is like.. 0.365
Change the Denominator (Bottom Number in Fraction) so they're the same:
6/8 3/8.
Now d'you see?
