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3 years ago

Please help solve this

Mathematics

2 answers:

Oksi-84 [34.3K]3 years ago

8 0

The answer is [3]. :))

Leni [432]3 years ago

4 0

The answer is 3,,,!’f

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∇f = λ∇g gives us the equations 4xy = 4λx, 2x2 = 8λy. The first equation implies that x = Incorrect: Your answer is incorrect. o

Vlad1618 [11]

Answer:

The answer is correct

Step-by-step explanation:

6 0

3 years ago

How many full glasses of water will be needed to fill the jug ? Jug= 2.8 litres, Cup= 200ml

igomit [66]

Answer:

14 cups

Step-by-step explanation:

1 l = 1000ml

to filled the jug we need 2.8 litres

2.8 l to ml

2.8 × 1000

= 2800ml

how many cup would give us 2800ml

2800 ÷ 200

=14 cups

3 0

2 years ago

A line passing (a,3) and (5,5) is perpendicular to a line passing through (0,0) and (1,a) Find the value of a.

vodka [1.7K]

Answer:

a = -5

Step-by-step explanation:

(5 - 3)/(5 - a)

2/(5 - a)

perpendicular of 2/(5 - a) = -(5 - a)/2

(a - 0)/(1 - 0) = -(5 - a)/2

a/1 = -(5 - a)/2

2a = -5 + a

a = -5

6 0

3 years ago

What is the range of the equation

a_sh-v [17]

The range of the equation is $y>2$

Explanation:

The given equation is $y=2(4)^{x+3}+2$

We need to determine the range of the equation.

Range:

The range of the function is the set of all dependent y - values for which the function is well defined.

Let us simplify the equation.

Thus, we have;

$y=2 \cdot 4^{x+3}+2$

This can be written as $y=2^{1+2(x+3)}+2$

Now, we shall determine the range.

Let us interchange the variables x and y.

Thus, we have;

$x=2^{1+2(y+3)}+2$

Solving for y, we get;

$x-2=2^{1+2(y+3)}$

Applying the log rule, if f(x) = g(x) then $\ln (f(x))=\ln (g(x))$ , then, we get;

$\ln \left(2^{1+2(y+3)}\right)=\ln (x-2)$

Simplifying, we get;

$(1+2(y+3)) \ln (2)=\ln (x-2)$

Dividing both sides by $\ln (2)$ , we have;

$2 y+7=\frac{\ln (x-2)}{\ln (2)}$

Subtracting 7 from both sides of the equation, we have;

$2 y=\frac{\ln (x-2)}{\ln (2)}-7$

Dividing both sides by 2, we get;

$y=\frac{\ln (x-2)-7 \ln (2)}{2 \ln (2)}$

Let us find the positive values for logs.

Thus, we have,;

$x-2>0$

$x>2$

The function domain is $x>2$

By combining the intervals, the range becomes $y>2$

Hence, the range of the equation is $y>2$

7 0

3 years ago

Simplify 28/184 by reducing to lowest form A) 1/46 B) 1/7 C) 14/92 D) 7/46

Elodia [21]

It’ll be D) 7/46 you can reduce it by dividing everything with 4

5 0

3 years ago

Please help solve this​

Please help solve this