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Gemiola [76]
3 years ago
14

Why does a rectangle with different side lengths have only 2 lines of symmetry?

Mathematics
1 answer:
ICE Princess25 [194]3 years ago
5 0

Answer:

C. all four angles are congruent, and opposite sides are congruent for a horizontal and vertical line of reflection

Step-by-step explanation:

A. isn't correct because all four sides aren't congruent, only the pair of opposite sides are congruent. Sense only opposite side are congruent you can only reflect the opposite sides onto each other and not diagonally meaning B. and D. are incorrect leaving C. all four angles are congruent, and opposite sides are congruent for a horizontal and vertical line of reflection as the correct answer

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A statistics practitioner determined that the mean and stan-dard deviation of a data set were 90 and 15, respectively. What can
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Answer:

If the distribution is bell shaped we can approximate the probability with high accuracy using the z score formula.

a) P(75

And for this case we can use the z score given by:

z = \frac{X-\mu}{\sigma}

And if we use it we got:

P(75

b) P(60

And for this case we can use the z score given by:

z = \frac{X-\mu}{\sigma}

And if we use it we got:

P(60

c) P(45

And for this case we can use the z score given by:

z = \frac{X-\mu}{\sigma}

And if we use it we got:

P(45

If the distribution is NOT bell shaped the approximation with the z score NOT works and we need to have the distribution for X in order to find the probabilities.

Step-by-step explanation:

Previous concepts

If the distribution is bell shaped we can approximate the probability with high accuracy using the z score formula.

The Z-score is "a numerical measurement used in statistics of a value's relationship to the mean (average) of a group of values, measured in terms of standard deviations from the mean".  

Part a

Let X the random variable of interest

We assume for this case that \mu=90 and \sigma=15

We are interested on this probability

P(75

And for this case we can use the z score given by:

z = \frac{X-\mu}{\sigma}

And if we use it we got:

P(75

Part b

P(60

And for this case we can use the z score given by:

z = \frac{X-\mu}{\sigma}

And if we use it we got:

P(60

Part c

P(45

And for this case we can use the z score given by:

z = \frac{X-\mu}{\sigma}

And if we use it we got:

P(45

If the distribution is NOT bell shaped the approximation with the z score NOT works and we need to have the distribution for X in order to find the probabilities.

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4 years ago
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