X = 1st integer, y = 2nd integer, z = 3rd integer
y = 2x
z = 2y......z = 2(2x)...z = 4x
y = x + 17
2x = x + 17
2x - x = 17
x = 17
y = 2x
y = 2(17)
y = 34
z = 4x
z = 4(17)
z = 68
and the sum would be : 17 + 34 + 68 = 119
Since a kilogram is 1000 grams, 4*1000=4000 kilograms, which is your answer
Answer:
88 ft^2
Step-by-step explanation:
For a rectangular prism with dimensions 1 ft by 8 ft by 4 ft, there are two opposite faces with dimensions
<em>1 ft by 8 ft, </em>
two opposite faces with dimensions
<em>1 ft by 4 ft, </em>
and two opposite faces with dimensions
<em>4 ft by 8 ft.</em>
We find their area and add them.
SA = 2 * 1 ft * 8 ft + 2 * 1 ft * 4 ft + 2 * 4 ft * 8 ft
SA = 16 ft^2 + 8 ft^2 + 64 ft^2
SA = 88 ft^2
Answer:
Step-by-step explanation:
Since the number of pages that this new toner can print is normally distributed, we would apply the formula for normal distribution which is expressed as
z = (x - µ)/σ
Where
x = the number of pages.
µ = mean
σ = standard deviation
From the information given,
µ = 2300 pages
σ = 150 pages
1)
the probability that this toner can print more than 2100 pages is expressed as
P(x > 2100) = 1 - P(x ≤ 2100)
For x = 2100,
z = (2100 - 2300)/150 = - 1.33
Looking at the normal distribution table, the probability corresponding to the z score is 0.092
P(x > 2100) = 1 - 0.092 = 0.908
2) P(x < 2200)
z = (x - µ)/σ/√n
n = 10
z = (2200 - 2300)/150/√10
z = - 100/47.43 = - 2.12
Looking at the normal distribution table, the probability corresponding to the z score is 0.017
P(x < 2200) = 0.017
3) for underperforming toners, the z score corresponding to the probability value of 3%(0.03) is
- 1.88
Therefore,
- 1.88 = (x - 2300)/150
150 × - 1.88 = x - 2300
- 288 = x - 2300
x = - 288 + 2300
x = 2018
The threshold should be
x < 2018 pages
Answer:
mean is equal to 5.12
Step-by-step explanation:
<em>We are given that 32% of college students work fulltime. We have to find the mean for the number of student s who are working full time in a sample of 16</em>
success rate, p = 32% = 0.32
Sample size is denoted as n = 16
The forumla of mean is given as
mean = sample size × success rate
mean = n × p
= 16 × 0.32
= 5.12
