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tatyana61 [14]
3 years ago
11

Whats the value of the six in 763,297

Mathematics
1 answer:
Arada [10]3 years ago
7 0

Answer:

60,000

or

sixty thousand

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Find the distance between each pair of points.
scoundrel [369]

Answer:

(-1, -1) and (-4,5)

Distance between them ,

\sqrt{   {( - 4 + 1)}^{2} +  {(5 + 1)}^{2} }

=  \sqrt{ {( - 3)}^{2}  +  {(6)}^{2} }

=  \sqrt{9 + 36}  =  \sqrt{45}  = 3 \sqrt{5}

Option B

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What is the value of y? Assume that the line is tangent to the circle
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c 120

Step-by-step explanation:

I'm thinking isit is c120

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please help :{ brainliest if you can get it right and I need you to prove why your answer is correct, thanksss​
beks73 [17]

Answer:

The Value of a=\frac{15}{4}.

Step-by-step explanation:

We have Named the figure please find the attachment for your reference.

Given:

PR = y

QR = a

RS = b

PS = z

PQ = x

QS = 15

∠P = 90°

∠R = 90°

∠Q = 60°

∠S = 30°

We need to find the Value of 'a'.

Solution:

Now we know that:

In Δ PQS

∠P = 90°

∠S = 30°

Now we know that;

sin\ \theta = \frac{opposite\ side}{Hypotenuse}

sin \ S= \frac{PQ}{QS}

Substituting the given values we get;

sin\ 30\°=\frac{x}{15}

Now we know that;

sin\ 30\° = \frac12

So we can say that;

\frac{1}{2}=\frac{x}{15}\\\\x=\frac{15}{2}

Now In Triangle PQR.

∠R = 90°

∠Q = 60°

So we can say that;

Cos \theta = \frac{adjacent \ Side}{Hypotenuse}\\

Cos\ Q = \frac{QR}{PQ}

Substituting the given values we get;

cos 60\°= \frac{a}{x}

Now we know that;

cos 60\°= \frac12

x=\frac{15}{2}

So substituting the values we get;

\frac{1}{2}=\frac{a}{\frac{15}{2}}

By Using Cross Multiplication we get;

a= \frac{1}{2}\times\frac{15}{2}\\\\a=\frac{15}{4}

Hence The Value of a=\frac{15}{4}.

6 0
3 years ago
An architectural drawing of a building shows the elevation of the basement floor to be –10 feet. The elevation of the roof is 40
m_a_m_a [10]
50 feet

It is 10 feet from -10ft to 0ft, plus 40ft to the roof.
8 0
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Given the trapezoid PQRS …. Please i need help ASAP.
navik [9.2K]
Q+P =180 so (Q is 137) p=s so (s is 43) and q = r so (r is 137)
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