The answer is 3 because it goes into 39 and 42 and 6 doesn't go into 39
A random variable can be either discrete or continuous. It is discrete it can assume only a finite number of values, or a countable infinity of values at most.
It is continuous if it can assume values in an interval, or in general, an uncountable infinity of values.
That being said, we have:
Option A is a discrete random variable, because the number of heads in 5 throws can be 0, 1, 2, 3, 4 or 5. So, we have finitely many possible values.
Option B is a discrete random variable, because the number you roll on a die is either1, 2, 3, 4, 5 or 6. So, we have finitely many possible values.
Option C is a discrete random variable, because if there are n students in a class, the number of boys is an integer between 0 and n. So, we have finitely many possible values.
Option D is finally a continuous random variable, because the height of a 10-year-old can be any number (in a suitable range of course).
I believe it would be -16k^3 + 3v^4 - 9k^3 + 6v^4
Answer:
2 n - 2 = n - 38
Step-by-step explanation:
Two fewer than "a number doubled"
2n-2 = n-38
