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joja [24]
2 years ago
12

Linear equations: word problems UFG

Mathematics
1 answer:
mrs_skeptik [129]2 years ago
4 0

The equation to find the number of assignments in the math section of Savannah's binder is 197 = x + 132

<h3>Equation</h3>

  • Assignment in the history, science, and art sections combined = 132 assignment

  • Assignment in the math section = x

  • Total assignment = 197 assignments

Total assignment = Assignment in math + Assignment in other subjects

197 = x + 132

197 - 132 = x

65 = x

Therefore, the equation to find the number of assignments in the math section of Savannah's binder is 197 = x + 132

Learn more about equation:

brainly.com/question/13729904

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To fulfill the requirements for a certain degree, a student can choose to take any 7 out of a list of 20 courses, with the const
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Complete answer:

Fulfill the requirements for a certain degree, a student can choose to take any 7 out of a list of 20 courses, with the constraint that at least 1 of the 7 courses must be a statistics course. Suppose that 5 of the 20 courses are statistics courses.

(a) How many choices are there for which 7 courses to take?

(b) Explain intuitively why the answer to (a) is not \binom{5}{1}\binom{19}{6}

Answer:

a) 71085 choices

b) See below

Step-by-step explanation:

a) First we're going to calculate in how many ways you can take 7 courses from a list of 20 without the constraint that at least 1 of the 7 courses must be a statistics course, that's simply a combination of elements without repetition so it's: \binom{20}{7}, but now we should subtract from that all the possibilities when none of the courses chose are a statistic course, that's is \binom{15}{7} because 15 courses are not statistics and 7 are the ways to arrange them. So finally, the choices for which 7 courses to take with the constraint that at least 1 of the 7 courses must be a statistics course are:

\binom{20}{7}-\binom{15}{7}=71085

b) It's important to note that the constraint at least 1 of the 7 courses must be a statistics course make the possible events dependent, we can not only fix an statistic course and choose the others willingly ( that is what \binom{5}{1}\binom{19}{6} means) because the selection of one course affect the other choices.

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Step-by-step explanation:

Consider the provided equation.

45(15x+20)-7x=56(12x-24)+6

We need to solve the equation for x.

Use the distributive property: a(b+c)=ab+ac

45(15x+20)-7x=56(12x-24)+6

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Add the like terms.

668x+900=672x-1338

Isolate the variable as shown:

672x-668x=900+1338

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x=\frac{2238}{4}

x=\frac{1119}{2}

Hence, the value of the equation for x is x=\frac{1119}{2} or 559.5.

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