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Vilka [71]
3 years ago
5

Please help me with this homework

Mathematics
2 answers:
vagabundo [1.1K]3 years ago
6 0

Answer:

-620

Step-by-step explanation:

beks73 [17]3 years ago
6 0

Answer:

-620

Step-by-step explanation:

You just need to do the ten's time tables

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If f(x)=-4x+1 what is f(-x/2)
guapka [62]

Answer:

f(\frac{-x}{2})=2x+1

Step-by-step explanation:

given f(x)=-4x+1................(1)

x=\frac{-x}{2}  put in equ (1)

f(x)=-4x+1

f(\frac{-x}{2} )  =-4(\frac{-x}{2})+1

 f(\frac{-x}{2})=2x+1 answer

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7 0
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<h2>B. x = -1, x = -3, y = 0</h2>

Step-by-step explanation:

g(x)=\dfrac{x-2}{x^2+4x+3}\\\\vertical\ asymptote:\\\\x^2+4x+3=0\\x^2+x+3x+3=0\\x(x+1)+3(x+1)=0\\(x+1)(x+3)=0\iff x+1=0\ \vee\ x+3=0\\\\\boxed{x=-1\ \vee\ x=-3}\\\\horizontal\ asymptote:\\\\\lim\limits_{x\to\pm\infty}\dfrac{x-2}{x^2+4x+3}=\lim\limits_{x\to\pm\infty}\dfrac{x^2\left(\frac{1}{x}-\frac{2}{x^2}\right)}{x^2\left(1+\frac{4}{x}+\frac{3}{x^2}\right)}=\lim\limits_{x\to\pm\infty}\dfrac{\frac{1}{x}-\frac{2}{x^2}}{1+\frac{4}{x}+\frac{3}{x^2}}=\dfrac{0}{1}=0\\\\\boxed{y=0}

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3 years ago
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Math work! Plz help!!
Svetllana [295]
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