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3 years ago

What is the average of 2 1/3 and 3 1/2

Mathematics

2 answers:

swat323 years ago

8 0

Answer:

2 11/12

Step-by-step explanation:

The average of 2 ⅓ and 3 ½ is 2 ‌11⁄12‌. To find the average, find the sum of the fractions and divide by 2.

2 ⅓ + 3 ½ = ‌7⁄3‌ + ‌7⁄2 = ‌14⁄6 + ‌21⁄6 = ‌35⁄6 or 5 5⁄6

5 5⁄6 ÷ 2 = 35⁄6 × 1⁄2 = 35⁄12 or 2 11⁄12

VikaD [51]3 years ago

7 0

The average of 2⅓ and 3½ is 2 11/12

2⅓ + 3½ = 7/3 + 7/2 = 14/6 + 21/6 = 35/6 or 5/6

5 5/6 ÷ 2 = 35/6 × 1/2 = 35/12 or 2 11/12

Finding the Average

Average refers to the sum of the values divided by the count. Therefore, the steps to follow to find the average are below:

Add the given values.

Divide the sum by the count of values.

Equation:

(2 1/3 + 3 1/2) / 2 = ?

Solution:

(2 1/3 + 3 1/2) / 2 = ?

* Change the mixed numbers to improper fractions.

= (7/3 + 7/2) / 2

* Add the fractions. Find the LCD.

= (14/6 + 21/6) / 2

= ( 35/6 ) /2

To divide change the sign to multiplication, The give the reciprocal of the second fraction

= 35/6 × 1/2

= 35/12 or 2 11/12

Final Answer:2 11/12

<h3>hope it helps you</h3><h3><u>Th</u><u>ank</u> <u>You</u> !!</h3>

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2 years ago

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Let f(x)=e^x and G(x)=x+6. What are the domain and range of g(f(x))?

Lena [83]

Answer:

Domain and Range of g(f(x)) are 'All real numbers' and {y | y>6 } respectively

Step-by-step explanation:

We have the functions, f(x) = eˣ and g(x) = x+6

So, their composition will be g(f(x)).

Then, g(f(x)) = g(eˣ) = eˣ+6

Thus, g(f(x)) = eˣ+6.

Since the domain and range of f(x) = eˣ are all real numbers and positive real numbers respectively.

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2 years ago

A food-packaging apparatus underfills 10% of the containers. Find the probability that for any particular 10 containers the numb

Maksim231197 [3]

Answer:

a) $P(X = 1) = 0.38742$

b) $P(X = 3) = 0.05740$

c) $P(X = 9) = 0.00000$

d) $P(X \geq 5) = 0.00163$

Step-by-step explanation:

For each container, there are only two possible outcomes. Either it is undefilled, or it is not. This means that we can solve this problem using the binomial probability distribution.

Binomial probability distribution:

The binomial probability is the probability of exactly x successes on n repeated trials, and X can only have two outcomes.

$P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}$

In which $C_{n,x}$ is the number of different combinatios of x objects from a set of n elements, given by the following formula.

$C_{n,x} = \frac{n!}{x!(n-x)!}$

And p is the probability of X happening.

In this problem

There are 10 containers, so $n = 10$ .

A food-packaging apparatus underfills 10% of the containers, so $p = 0.1$ .

a) This is P(X = 1)

$P(X = 1) = C_{10,1}.(0.1)^{1}.(0.9)^{9} = 0.38742$

b) This is P(X = 3)

$P(X = 3) = C_{10,3}.(0.1)^{3}.(0.9)^{7} = 0.05740$

c) This is P(X = 9)

$P(X = 9) = C_{10,9}.(0.1)^{9}.(0.9)^{1} = 0.00000$

d) This is $P(X \geq 5)$ .

Either the number is lesser than five, or it is five or larger. The sum of the probabilities of each event is decimal 1. So:

$P(X < 5) + P(X \geq 5) = 1$

$P(X \geq 5) = 1 - P(X < 5)$

In which

$P(X < 5) = P(X = 0) + P(X = 1) + P(X = 2) + P(X = 3) + P(X = 4)$

$P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}$

$P(X = 0) = C_{10,0}.(0.1)^{0}.(0.9)^{10} = 0.34868$

$P(X = 1) = C_{10,1}.(0.1)^{1}.(0.9)^{9} = 0.38742$

$P(X = 2) = C_{10,2}.(0.1)^{2}.(0.9)^{8} = 0.1937$

$P(X = 3) = C_{10,3}.(0.1)^{3}.(0.9)^{7} = 0.05740$

$P(X = 4) = C_{10,4}.(0.1)^{1}.(0.9)^{9} = 0.38742$

$P(X < 5) = P(X = 0) + P(X = 1) + P(X = 2) + P(X = 3) + P(X = 4) = 0.34868 + 0.38742 + 0.19371 + 0.05740 + 0.01116 = 0.99837$

Finally

$P(X \geq 5) = 1 - P(X < 5) = 1 - 0.99837 = 0.00163$

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I believe it would be 5/9

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