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3 years ago

What is a value or values that make an equation true

1 answer:

7 0

Any value that satisfies the equality.
E.g. 2x + 4x = 10 the value that makes this true is 2

or

x^2 = 2 The values that would make it true are 4 and -4, since the squared of any number is always a positive.

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5 times the difference between 19 and 13

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5 times 19-13 would equal 30 as 19-13 is 6 times 5 =30

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in any strategic-form game, if a player has a dominant strategy, then all of the other strategies of that player are dominated (

Vsevolod [243]

Answer:

Dominant strategy is an in game theory that refers to the optimal option for a player among all the competitive strategies, no matter how that player's opponents may play.

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If there is a 30% chance of sun tomorrow and a 40% chance of wind and no sun, what is the probability that it is windy, given th

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A, 57%, because 0.40 divided by all possible outcomes, which is 0.70 because we know it will not be sunny tomorrow, is 0.57.

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3 years ago

Read 2 more answers

13-6x=(2x-5)^2+3 what answer

svet-max [94.6K]

13−6x=(2x−5)2+3Step 1: Simplify both sides of the equation.−6x+13=4x2−20x+28Step 2: Subtract 4x^2-20x+28 from both sides.−6x+13−(4x2−20x+28)=4x2−20x+28−(4x2−20x+28)−4x2+14x−15=0Step 3: Use quadratic formula with a=-4, b=14, c=-15.x=−b±√b2−4ac2ax=−(14)±√(14)2−4(−4)(−15)2(−4)x=−14±√−44−8

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3 years ago

Write an equation of the circle that has a diameter with endpoints (12, 3) and (-18,3).

Mademuasel [1]

The equation of the circle that has a diameter with endpoints (12, 3) and(-18,3) is x² + y² + 6x - 6y - 207 = 0

<h3>Coordinates of center of circle</h3>

Since the endpoints of the diameter are (x₁, y₁) = (12,3) and (x₂, y₂) = (-18,3), the coordinates of the center of the circle are the midpoints of the diameter. So, the midpoints are

x = (x₁ + x₂)/2 = (12 + (-18))/2 = (12 - 18)/2 = -6/2 = -3 and
y = (y₁ + y₂)/2 = (3 + 3)/2 = 6/2 = 3.

So, the coordinates of the center of the circle are (-3, 3)

<h3>The radius of the circle</h3>

The radius of the circle r = √[(x₁ - h)² + (y₁ - k)²] where

(x₁, y₁) = coordinates of end of diameter = (12, 3) and

(h, k) = coordinates of center of circle = (-3, 3)

So, substituting the values of the variables into r, we have

r = √[(x₁ - h)² + (y₁ - k)²]

r = √[(12 - (-3))² + (3 - 3)²]

r = √[(12 + 3)² + 0²]

r = √[15² + 0²]

r = √15²

r = 15

<h3>The equation of the circle</h3>

The equation of a circle with center (h,k) is given by

(x - h)² + (y - k)² = r² where r = radius of circle.

Substituting the values of the variables into the equation, we have

(x - h)² + (y - k)² = r²

(x - (-3))² + (y - 3)² = 15²

(x + 3)² + (y - 3)² = 15²

x² + 6x + 9 + y² - 6y + 9 = 225

x² + 6x + y² - 6y + 9 + 9 - 225 = 0

x² + y² + 6x - 6y - 207 = 0

The equation of the circle that has a diameter with endpoints (12, 3) and(-18,3) is x² + y² + 6x - 6y - 207 = 0

Learn more about equation of a circle here:

brainly.com/question/18435467

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