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kumpel [21]
3 years ago
5

If a =5 b =6 and c=a-2 . answer the question , 8a-2b+1c

Mathematics
1 answer:
azamat3 years ago
3 0

Answer:

here <em>given.</em><em>,</em>

a =5 b =6 and c=a-2(5-2=3)

putting the given value in the equation...we get..

=8*5-2*6+1*3

=40-12+3

=43-12

=31

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The bacteria culture starts with 500 bacteria and doubles size every half hour.= 2 hours

32,000

Thus, after three hours, the population of bacteria is 32,000.= 3 hours

A bacteria culture starts with 500 bacteria and doubles in size every half hour.1

(a) How many bacteria are there after 3 hours?

We are told “. . . doubles in size every half hour.” Let’s make a table of the time and population:

t 0 0.5 1.0 1.5 2.0 2.5 3.0

bacteria 500 1000 2000 4000 8000 16000 32000

Thus, after three hours, the population of bacteria is 32,000.

(b) How many bacteria are there after t hours?

In t hours, there are 2t doubling periods. (For example, after 4 hours, the population has doubled 8

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P(t) = 500 · 2

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This is an acceptable response, but in calculus and all advanced mathematics and science, we will

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P(t) = P0e

rt

We are given that the initial population is 500 bacteria. So P0 = 500 and we have

P(t) = 500ert

We know that after 1 hour, there are 2000 bacteria. (We could’ve used any other pair from our table

that we wish.) Substituting into our function, we get

P(t) = 500ert

2000 = 500er·1

2000 = 500er

1

500

· 2000 =

1

500

· 500er

4 = er

and now we use the natural logarithm to solve for r

ln (4) = ln (er

)

ln (4) = r · ln (e)

ln (4) = r

1.3863 ≈ r

Thus the function P(t) = 500e1.3863t gives the number of bacteria after t hours.

(c) How many bacteria are there after 40 minutes?

The input t to our function is given in hours, so we must convert 40 minutes into hours. So (40 min)

1 hr

60 min

=

2

3

hr.

P(t) = 500e1.3863t

P

2

3

= 500e1.3863·(2/3)

P

2

3

≈ 1259.9258

Thus, after 40 minutes (2/3 of an hour), there are about 1260 bacteria.

(d) Graph the population function and estimate the time for the population to reach 100,000.

50000

100000

1 2 3 4 5

b

(3.8219, 100,000)

t

P

Using the calc:intersect on the TI-84, we get the point (3.8219, 100000), thus the population will

reach 100,000 in about 3.82 yrs

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